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GuDViN [60]
3 years ago
6

What is the slope and the y intercept of Y=-2/3x+1

Mathematics
1 answer:
siniylev [52]3 years ago
6 0
It should be 25 or 20 because the way the problem is set up you should already have your answer of 2020
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Find the total surface area of the cube-shaped gift below
garri49 [273]

Answer:

24

Step-by-step explanation:

:)

6 0
3 years ago
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How do i solve this question 58−(14)2
Naily [24]

Answer:

PEMDAS RULE

Step-by-step explanation:

STEP one is multiplication 58-14x2=58-28

STEP two is subtraction 58-28=30

Parenthesis

Exponent

Multiplication

Division

Addition

Subtract

3 0
3 years ago
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From first principle find the derivative of logx​
Archy [21]

Hello!

\large\boxed{\frac{dy}{dx}logx = \frac{1}{xln10}  }

Recall that:

logx can be rewritten as:

log_{10}x

Use the equation for the derivative of a log expression:

\frac{dy}{dx}log_{a}u = \frac{1}{ulna} * u'

Substitute in the values in the expression:

logx = \frac{1}{xln10} * 1 = \frac{1}{xln10}

4 0
3 years ago
Find the measures of EAF DAE and CAD
sdas [7]
You have to build an equation to find the answer,

angles in a straight line add upto 180° 
so your equation would be,

12x+30°=180°
      -30    -30
=12x=150°
   ÷12  ÷12
=x=12.5°

now find the measures of the angles by using 12.5 as x.

angle EAF= 2x
                 =2×12.5
                 =25° degrees

angle DAE= 4x
                 =4×12.5
                 =50°degrees

angle CAD=6x
                 =6×12.5
                 =75°degrees

check,
30+25+50+75=180°degrees

hope this helps.......
7 0
3 years ago
A pyramid has a square base of length 8cm and a total surface area of 144cm². Find the volume of the pyramid. (Please use Pythag
Sveta_85 [38]

Answer:

\displaystyle V_{ \text{pyramid}}= 64 \:  {cm}^{3}

Step-by-step explanation:

we are given surface area and the length of the square base

we want to figure out the Volume

to do so

we need to figure out slant length first

recall the formula of surface area

\displaystyle A_{\text{surface}}=B+\dfrac{1}{2}\times P \times s

where B stands for Base area

and P for Base Parimeter

so

\sf\displaystyle \: 144=(8 \times 8)+\dfrac{1}{2}\times (8 \times 4) \times s

now we need our algebraic skills to figure out s

simplify parentheses:

\sf\displaystyle \: 64+\dfrac{1}{2}\times32\times s = 144

reduce fraction:

\sf\displaystyle \: 64+\dfrac{1}{ \cancel{ \: 2}}\times \cancel{32}  \: ^{16} \times s = 144 \\ 64 + 16 \times s = 144

simplify multiplication:

\displaystyle \: 16s + 64 = 144

cancel 64 from both sides;

\displaystyle \: 16s = 80

divide both sides by 16:

\displaystyle \: \therefore \: s = 5

now we'll use Pythagoras theorem to figure out height

according to the theorem

\displaystyle \:  {h}^{2}  +  (\frac{l}{2} {)}^{2}  =  {s}^{2}

substitute the value of l and s:

\displaystyle \:  {h}^{2}  +  (\frac{8}{2} {)}^{2}  =  {5}^{2}

simplify parentheses:

\displaystyle \:  {h}^{2}  +  (4 {)}^{2}  =  {5}^{2}

simplify squares:

\displaystyle \:  {h}^{2}  +  16  =  25

cancel 16 from both sides:

\displaystyle \:  {h}^{2}   =  9

square root both sides:

\displaystyle \:   \therefore \: {h}^{}   =  3

recall the formula of a square pyramid

\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h

where A stands for Base area (l²)

substitute the value of h and l:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times  \{8 \times 8 \}\times 3

simplify multiplication:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times  64\times 3

reduce fraction:

\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times  64\times \cancel{ \:  3}

hence,

\sf\displaystyle V_{ \text{pyramid}}= 64 \:  {cm}^{3}

8 0
3 years ago
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