Answer:
Complete question is attached with.
Both the triangles are congruent by ASA property of congruence and the segment RT is congruent to FD.
Step-by-step explanation:
From angle sum property of the triangle we can find the measure of the missing angles.
As for
we can find
which is ![180-(60+80)=40](https://tex.z-dn.net/?f=180-%2860%2B80%29%3D40)
And for
we can find
which is ![180-(60+40)=80](https://tex.z-dn.net/?f=180-%2860%2B40%29%3D80)
To find the congruence.
We see that
and ![\angle E=80\ (deg)](https://tex.z-dn.net/?f=%5Cangle%20E%3D80%5C%20%28deg%29)
Then
along with ![\angle F=60\ (deg)](https://tex.z-dn.net/?f=%5Cangle%20F%3D60%5C%20%28deg%29)
Between these two angles we have a segment that is equal in measure.
So two angles and a side in continuation, we can apply ASA property of congruence.
Now segment
and segemnt
are congruent as both the segment have equal measures on it.
So finally option A is the correct choice and both the triangles are congruent by ASA property.
And RT is congruent with FD.
It appears that none of your option choices are correct,, are you sure you copied them right ? I will show you how to solve this and how I got my answer.
The first step for solving this is to add the numbers in the parenthesis.
3 × 11 × 2 - 14 ÷ 7
Divide -14 by 7.
3 × 11 × 2 - 2
Divide the first 3 numbers together.
66 - 2
Subtract the numbers together to get your final answer.
64
Let me know if you have any further questions.
:)
Answer:
C. 4
Step-by-step explanation:
first off, we know we need the value of HJ to solve for GH. Luckily for us HJ is congruent to JK, and we have the values to solve for that using pythagorean theorum.
4^2 + JK^2 = 5^2
16 + JK^2 = 25
JK^2 = 9
JK = 3
now we can solve for GH
3^2 + GH^2 = 5^2
9 + GH^2 = 25
GH^2 = 16
GH = 4
I pretty sure this one is b