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Zarrin [17]
3 years ago
15

7. What is the slope in the equation y=-6x+4?

Mathematics
1 answer:
lana [24]3 years ago
5 0
7. The slope is the number with the x next to it, so it would be -6x

8. The y-Intercept is the number WITHOUT the x, in this case would be -5

9. You always want the equation to be in y = M(slope)x + b(y-intercept). Subtract 2x on both sides to get 4y = -2x + 12. Divide both sides by 4 to leave y by itself. That leaves us with y = -1/2 + 3

10. Same thing minus x on both sides to get -3y = -x + 6. And since you don’t want a negative y, you need to divide by a negative. Divide both sides by -3 to get y = 1/3 -2. When you divide a number by a negative, it changes the sign in front of the number.
Hope this helps!
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Is 6(x+0.4) equivalent to 3(2x+0.8)? YES or NO???????
amm1812

Answer:

Yes

Step-by-step explanation:

If we multiply them out, we get 6x + 2.4 for the first one and 6x + 2.4 for the second one, therefore they are the same.

3 0
2 years ago
Solve the following system: (5 points)
dusya [7]
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3 0
2 years ago
X^2-x+2=0<br> Please use the quadratic formula
Ainat [17]

Answer:

\boxed{\sf x=\cfrac{1\pm \sqrt{-7} }{2}}

Step-by-step explanation:

\sf x^2-x+2=0

<u>Use quadratic formula:</u>

\boxed{\sf \frac{-b\pm \sqrt{b^2-4ac}}{2a}}

\sf a=1, b=-1, c=2

___________________________

\sf x_1,_2=\cfrac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\times \:1\times \:2}}{2\times \:1}

  • \sf \sqrt{\left(-1\right)^2-4\times \:1\times \:2}
  • \sf =\sqrt{-7}

_________________

\sf x_1,_2\cfrac{-\left(-1\right)\pm \sqrt{-7}}{2\times \:1}

  • \sf -(-1)=1
  • 2\times 1=2

\sf x_1,_2=\cfrac{1\pm \sqrt{-7} }{2}

_______________________________________

<u>Learn more: brainly.com/question/22286698</u>

4 0
2 years ago
What is h^2+6h-27 ????????????​
nydimaria [60]

Answer:

Sorry it's acually (h+3)(h-9)

4 0
2 years ago
I need help with my Clock
anyanavicka [17]
5 -> 15

6 -> 20

7 -> 25

8 -> 30

9 -> 35

10 -> 40

then in ones:

after 41 would be 42 and 43


the elapsed time would be 43 minutes :)

hope this helps :)




8 0
2 years ago
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