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ollegr [7]
3 years ago
11

What is the value of 6x-4 when x=-5??

Mathematics
1 answer:
julia-pushkina [17]3 years ago
4 0

Answer:

-34

Step-by-step explanation:

6(-5)-4

-30-4

-34

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Can someone help me with this equation y=-x+4 and y=3x
dolphi86 [110]

Answer:

(1 , 3)

Step-by-step explanation:

y = -x + 4

y = 3x

=> -x + 4 = 3x

=> 4x = 4

=> x = 1

y = 3(1) = 3

Solution is (1 , 3)

7 0
3 years ago
Read 2 more answers
Find the difference and write it in simplest form 7 3/8 - 2 7/9
Papessa [141]
Well first you have to turn the mixed number into a improper fraction.
7 2/8=59 over 8
2 7/9=25 over 9
Then u would multiply the 59 by 9 and 8 by 9 and u should get 531 over 72 and for the second fraction u should multiply the 25 by 8 and the 9 by 8 and you should get 200 over 72 as a improper fraction.
Then you have to subtract 531 over 72 by 200 over 72 and u should get 231 over 72 which is 4 and 43 over 72 when simplified.
The answer: 4 43/72
Hope this helps!!!!

4 0
4 years ago
Solve 2 – 4&lt;5. Graph the solution.<br> The solution is
Arturiano [62]

Answer:

x < 9

Step-by-step explanation:

Move the -4 over as if there was an equal sign so that x < 9

Take the arrow that looks like this "<---O" that is not filled in and put it on the number 9.

Let me know if this helps <3

6 0
2 years ago
Read 2 more answers
If 2(a^2+b^2)=(a+b)^2 then, <br> &gt;a+b=0,<br> &gt;ab=0,<br> &gt;a=b,<br> &gt;2a=b
Tasya [4]

Answer:

2·(a^2 + b^2) = (a + b)^2

2·a^2 + 2·b^2 = a^2 + 2·a·b + b^2

a^2 + b^2 = 2·a·b

a^2 - 2·a·b + b^2  = 0

(a - b)^2 = 0

a = b


7 0
3 years ago
Solve the following system by the comparison method.
agasfer [191]

Answer:

2p + q = 1

9p + 3q + 3 = 0

q = 1 - 2p

replace q = 1 - 2p into 9p + 3q + 3 = 0

9p + 3(1 - 2p) + 3 = 0

9p + 3 - 6p + 3 = 0

3p + 6 =0

3p = -6

p = -2

q = 1 - 2p

q = 1 -2(-2)

q = 1 + 4

q = 5

(-2 , 5)

there for the answer would be

{(-2, 5)}

Hopefully this was helpful <3 :3

5 0
3 years ago
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