Answer:
-1/4
Step-by-step explanation:
2-1 over -3-1 = 1/-4
Answer:
law of cosines states c^2=a^2+b^2-2abc
b^2=26^2+24^2-2(26×24)cos 134°
b^2=676+576-1248cos134°
cos134= -0.6946
b^2=1252-12(-0.6946)
12×(-0.6946)= -8.3352
b^2=1252-(-8.3352)
b^2=1252+8.3352
b^2=1260.33
b=√1260.33
b=35.50
Well if you subtract 437.5 from 500 you get 62.5 that is the difference between them but in fraction form it would be 5/8.
Answer:
83 adult tickets and 217 student tickets.
Step-by-step explanation:
Let number of adult tickets sold = 
Given that total number of tickets = 300
So, number of student tickets = 300 - 
Cost of adult ticket = $15
Cost of student ticket = $11
Total collection from adult tickets = $
Total collection from student tickets = 
Given that overall collection = $3630

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.
Now , collection = $3632