3x+2y>6 x-y<1 graphing and shading

Mathematics

1 answer:

Taya2010 [7]2 years ago

3 0

$3x + 2y > 6x - y < 1$

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After 1 year, $800 deposited in a savings account with simple interest had earned $64 in

stepan [7]

Answer:

Step-by-step explanation:

We will use the equation provided to solve this problem.

$I=Prt$

Lets plug in the values:

$64=800x(1)$ First, divide both sides by 800.

$.08=x(1)$ Multiply x by 1

$x = .08$

Now, we multiply .08 by 100 to get our interest rate:

(.08)100 = 8

The interest rate is 8%

7 0

3 years ago

P(x)= 3x^3-5x^2-14x-4

nexus9112 [7]

$\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\
$

$\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)$

$\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm \sqrt{4+16}}{2}=\frac{2\pm \sqrt{20}}{2}=\frac{2\pm 2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}$

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2 years ago

Solve the equation 4y-2=26 A y=7 B y=6 C y=3 D Y=26

Lady_Fox [76]

If 4y-2=26 then 4y=26+2
4y=28 divide both side by 4
y=28/4=7 opt A

6 0

3 years ago

Read 2 more answers

247x82 using in area model

vovikov84 [41]

247x82=534 5 go in the hundreads place 3 go in the tens place and 4 go in the ones place

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