Answer:
44 2/4
Step-by-step explanation:
178/4= 44.5
44 2/4 =
44 x 4 = 176
176 + 2 = 178
hope this helps and if it is wrong i am sorry
you have a quadratic equation that can be factored, like x2+5x+6=0.This can be factored into(x+2)(x+3)=0.
So the solutions are x=-2 and x=-3.
2.
<span><span>1. Try first to solve the equation by factoring. Be sure that your equation is in standard form (ax2+bx+c=0) before you start your factoring attempt. Don't waste a lot of time trying to factor your equation; if you can't get it factored in less than 60 seconds, move on to another method.
</span><span>2. Next, look at the side of the equation containing the variable. Is that side a perfect square? If it is, then you can solve the equation by taking the square root of both sides of the equation. Don't forget to include a ± sign in your equation once you have taken the square root.
3.</span>Next, if the coefficient of the squared term is 1 and the coefficient of the linear (middle) term is even, completing the square is a good method to use.
4.<span>Finally, the quadratic formula will work on any quadratic equation. However, if using the formula results in awkwardly large numbers under the radical sign, another method of solving may be a better choice.</span></span>
The equation line passing through a point is understood to be parallel to the x-axis. In this case, the equation should be expressed as y = b where b is any number. Since y = 14 in the point (1,14), the equation of horizontal line passing through this point is y = 14.
Perimeter= (2 x Length) + (2 x width)
Do to find width:
Width= perimeter - (2 x length)
So now substitute in an equation
W= 154 - (55 x 2)
W= 154-110= 44
Remember 44 would equal the width when it is multiplied by 2. Now you have to divide by 2 to get the original.
Answer is 22
Answer:
(0 , -a²)
Step-by-step explanation:
tangent at x = a and x = -a
y = x² (a , a²) and (-a , a²) must be on the curve and tangent to curve
gradient dy/dx = 2x
slope (m) at x = a is <u>2a</u> and slope (m') at x=-a is<u> -2a</u>
line1: (y - a²) / (x - a) = 2a
y - a² = 2a (x - a) y = 2ax - a² ... (1)
line2: (y - a²) / (x + a) = - 2a y = -2ax- a² ... (2)
(1) - (2): 4ax = 0 a≠0 x = 0
y = - a²
I wish I did it right, or ....
