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3 years ago

HELP MEEE

Mathematics

1 answer:

EastWind [94]3 years ago

8 0

Sorry for what happened but the equation is a bit hard so
I think the answer is y=-2x+6

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20 POINTS

victus00 [196]

Ni is not correct. To solve the equivalent quarterly interest rate, the annual interest rate should be multiplied by the correct ratio. Since the annual interest rate is 4% per year. So in 1 quarter is equal to 0.25 year.

<span>(4% / year) (0.25 year/ 1 quarter) = 1% per quarter</span>

8 0

3 years ago

The formula t=√h/4 represents the time t in seconds that it takes an object to fall from a height of h feet. If a rock falls fro

raketka [301]

Answer:

it would take 14mph

Step-by-step explanation:

8 0

3 years ago

A circle has a radius of 32 units. Find the circumference. Round your answer to the nearest hundredth

meriva

The answer to the question is 201.06

7 0

3 years ago

Read 2 more answers

Stacy has $500 in her bank account at the beginning of the summer she wants to have no less than 200 in the account by the end o

Papessa [141]

Answer: Summer has 13 weeks so 18 x 13 is 234 and 500-234 is 266 so she can do it for 16 weeks

4 0

3 years ago

A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

harkovskaia [24]

Answer:

The value is $P_o = \$ 561958.9$

Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

$\frac{P_o}{168587.7} = \frac{600}{180}$

=> $P_o = \frac{600}{180} * 168587.7$

=> $P_o = \$ 561958.9$

8 0

3 years ago