50 points for answer.
2 answers:
Answer:
Point C: (4, 0)
Step-by-step explanation:
Parallelograms are quadrilaterals with two pairs of parallel sides, this means they will have the same slope between two line segments.
point slope form between two points: y - y1 = m (x - x1)
point A (2, 6) and D (4,4):
slope: point form, 6 - 4 = m(2 - 4)
2 = -2m
m (slope) = =
now that you know the change in position, apply this to vertice B to get the position of the final vertice.
B(2, 2)
C (2 +2, 2-2) = C(4, 0)
The final position of C vertice for parrallelogram A(2,6), B(2,2), D(4,4) will be C(4,0)
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Answer:
1) There are 100 carbon-14 atoms in the wood when it died
2) A function that models the number 'N' of carbon-14 atoms present in the wood (t) years after it died is presented as follows;
Step-by-step explanation:
The given parameters are;
The number of carbon-12 for each carbon-14 atom ≈ 10¹² carbon-12 atoms
The number of carbon-12 in the piece of wood = 10¹⁴ carbon-12 atoms
The number of carbon-14 in the piece of wood = 40 carbon-14 atoms
The number of carbon-12 in an organism = Constant
The number of carbon-14 in an organism = Decays
1) Given that the number of carbon-12 in an organism is constant, and there are 10¹² carbon-12 atoms per each carbon-14 atom, therefore, we have;
The number of carbon-12 atoms in the wood when it died = 10¹⁴ carbon-12 atoms
The number of carbon-14 atoms in the wood when it died = (10¹⁴ carbon-12 atoms)/(10¹² carbon-12 atoms/(carbon-14 atom)) = 100 carbon-14 atoms
The number of carbon-14 atoms in the wood when it died = 100 carbon-14 atoms
2) The half life of a radioactive isotope is given by the following formula;
The half life of carbon-14 atoms, ≈ 5,730 years
N₀ = The amount of carbon-14 present in the wood when it died = 100 carbon-14 atoms
Therefore, we have;
The number, N, of carbon-14 atoms present in the wood (t) years after it died is given as follows;