Answer:
![1\:\mathrm{pound}](https://tex.z-dn.net/?f=1%5C%3A%5Cmathrm%7Bpound%7D)
Step-by-step explanation:
We can write the following equation using the information given:
, where
is some constant.
Solving, we get:
.
Therefore, we plug in
to find the amount of meat he uses for each type:
Beef: ![3x=3(1)=3\:\mathrm{pounds}](https://tex.z-dn.net/?f=3x%3D3%281%29%3D3%5C%3A%5Cmathrm%7Bpounds%7D)
Pork:
.
Answer:
depends what u get in the roots whether the number is ![\sqrt{9} or \sqrt{-9}](https://tex.z-dn.net/?f=%5Csqrt%7B9%7D%20%20%20or%20%5Csqrt%7B-9%7D)
if it is square root -9 its gonna be 3i compared to just 3
The possible error made by Beth is directly multiplying scale of 5 to area of original triangle and getting area of enlarged triangle, which is wrong.
Step-by-step explanation:
Originally Triangle has height =3.5cm and width=4cm
Beth enlarged the same triangle by scale of 5 and calculate area of triangle
The area of triangle as given as A= ![\frac{1}{2} \texrm{ (base) (height)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Ctexrm%7B%20%28base%29%20%28height%29%7D)
Area of original triangle is A =
Since, The triangle is enlarged by scale of 5
New height =3.5x5 = cm and new width=4x5cm
Area of new triangle is
A' =
A' =
A' =
A' = ![A (5^{2})](https://tex.z-dn.net/?f=A%20%285%5E%7B2%7D%29)
Now, Looking what error beth made is:
Beth found Area of new triangle is A' =
The possible error made by Beth is directly multiplying scale of 5 to area of original triangle and getting area of enlarged triangle, which is wrong.
Pythagorus Theorm
a sqr + b sqr = c sqr
25 sqr + 7 sqr = c sqr
625 + 49 = c sqr
625 + 49 = 674
c = sqr root of 674
c = 25.96 (rounded to 2dp)