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grandymaker [24]
3 years ago
5

I have been saving up for a 2002 Jeep Grand Cherokee. The car costs $6,000. As of now, I have saved

Mathematics
1 answer:
BigorU [14]3 years ago
5 0
It would take 28 weeks 6000-2500=3500

3500/125

28
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I can’t figure out what the half circle means the answer options are 163,129,149 and 186
vodka [1.7K]

Answer: 129

Step-by-step explanation: First find the area of the circle. Since we know the area of a circle is πr²  (pi multiplied by the radius squared) we can find the area of the half circle. The radius is 5 (because radius is half of the diameter)

Area=3.14(5)²

       =3.14(25)

       =78.5

But since this is just a half circle, divide this by 2

That will get 39.25

Then add this to the area of the rectangle (L*W) which is 90

That will get about 129

4 0
3 years ago
Questions is in the picture. no links please illl give brainly and 50 points only if answered properly
ohaa [14]

Answer:

subtract

a) 13/20

b) 1/2

c) 5/24

d) 7/18

e) 7/20

f) 3/40

Add or subtract

a) 4/9

b) 1/2

c) 11/20

d) 1/4

e) 19/12 <u>or </u>1 \frac{7}{12}

f) 4/21

3 0
3 years ago
Read 2 more answers
The original selling price was $179.39 the sale price was $154.15 what was the percent mark down
natima [27]

Answer:

25.24 was the mark down

16.374%

Step-by-step explanation:

4 0
2 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
I am so confused! Can anyone help me with this trig problem?
Dominik [7]

\frac{5\pi }{4} or \frac{7\pi }{4}

divide both sides by 2

sinΘ = - \frac{\sqrt{2} }{2}

Since the sin ratio is negative then Θ is in third / fourth quadrants

Θ = sin^{- 1} (\frac{\sqrt{2} }{2}) = \frac{\pi }{4} related acute angle

Θ = ( π + \frac{\pi }{4} ) = \frac{5\pi }{4}

or Θ = ( 2π - \frac{\pi }{4} ) = \frac{7\pi }{4}




4 0
3 years ago
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