There are a total of 33 students in the class (21+12=33). There are 12 boys in the class so the chance of drawing a boys name would be 12/33 which reduces to 4/11. This means you will draw a boys name 4 times for every 11 draws. To find the percent probability, just divide...
4/11 =.3636
multiply by 100 to convert to a percentage ( move decimal to the right 2 places).
.3636 = 36.36%
There is a 36.36% chance that a boys name is drawn.
Answer:
The equation is
x =
Step-by-step explanation:
The Equation is formed from two sides equal to each other
- In the algebraic statement "is" means equal
- In the algebraic statement "of" means times (×)
∵ One eighth means 
∴ Negative one eighth means 
→ Assume that the number is x
∵ "of" means times
∴ Negative one eighth of a number =
× (x)
∴ Negative one eighth of a number =
x
∵ Negative one eighth of a number is 
→ "is" means equal, so the left side is
x and the right side is 
∴
x =
⇒ Equation
∴ The equation is
x =
Answer:
I don't know what you need
Step-by-step explanation:
Eliminate p :
2 (m + 2n + 2p) + (-1) (3m - n + 4p) = 2 (4) + (-1) 25
2m + 4n + 4p - 3m + n - 4p = 8 - 25
-m + 5n = -17
(m + 2n + 2p) + 2 (3m + 2n - p) = 4 + 2 (-4)
m + 2n + 2p + 6m + 4n - 2p = 4 - 8
7m + 6n = -4
Eliminate m :
7 (-m + 5n) + (7m + 6n) = 7 (-17) + (-4)
-7m + 35n + 7m + 6n = -119 - 4
41n = -123
Solve for n :
n = -3
Solve for m :
-m + 5 (-3) = -17
-m - 15 = -17
m = 2
Solve for p :
2 + 2 (-3) + 2p = 4
2 - 6 + 2p = 4
2p = 8
p = 4
The empty set (or null set) is a subset of every set.