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VikaD [51]
3 years ago
15

2.4x10^2+7.6x10^-1 awnser quick

Mathematics
2 answers:
solmaris [256]3 years ago
7 0
Im pretty sure it’s 182.4
timurjin [86]3 years ago
5 0
= 2.4 x 100 x 7.6 x 0.1
= 182.4
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The number of ferryboat trips r(c) needed to transport c cars in 1 day can be found using the function f(c)=c/20. If there are n
xz_007 [3.2K]
<h2>Hello!</h2>

The answer is:

The range of the given function, f(c) is

f(c)\leq 250

<h2>Why?</h2>

To solve the problem we need to remember that a function is a relationship between an input usually called "x" (domain) and an output, usually called "y" and it's also the range of the function.

f(x)=y

We are given a relationship (a function) between the ferryboat trips "c" and the number of cars transported per day.

f(c)=\frac{c}{20}

Also, we know that there are not more than 5000 cars transported by the ferryboat, so, let's make this value our input, in order to find the output (range) of the given function.

So, if

c=5000

Evaluating, we have:

f(5000)=\frac{5000}{20}=250

Hence, the range of the function knowing that there are not more than 5000 cars transported by the ferryboat (daily) the range is all the numbers that are less or equal to 250.

f(c)\leq 250

Have a nice day!

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3 years ago
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