6/5<13/10
6/5=120/100
6/5>11/10
(6/5 =12/10)
Approximately 70% of the visitors to the theme park are older than about 12.3.
A z-score of about -0.53 is position on the normal distribution for finding the amount above 30% (70%).
Therefore, we can write and solve the following equation:
(x - 15) / 5.2 = -0.53
x - 15 = -2.756
x = 12.244
The closest amount is 12.3.
Answer:
Step-by-step explanation:
Given that Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is selected at random
the probability
(a) The student is enrolled in mathematics=
(b) The student is enrolled in English.=
(c) The student is enrolled in both.=
(d) The student is enrolled in mathematics or English.=
(e) The student is enrolled in English but not in mathematics.
=
(f) The student is not enrolled in English or is enrolled in mathematics.
=
Things we know:
Six total pots = # of 10" + # of 8"
$78 total = cost of 10" + cost of 8"
So:
6 = x +y
and
78 = x*(cost of x) + y * (cost of y)
78 = x*12 + y*15
We need:
x+y=6 AND 12x+15y=78
So our answer can only be B.
Step-by-step explanation:
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