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ipn [44]
3 years ago
7

PLSSS HELP IF YOU TURLY KNOW THISS

Mathematics
1 answer:
SashulF [63]3 years ago
7 0

Answer:

11

Step-by-step explanation:

when you have to multiply exponents like that, you just add them. and with division you subtract

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Grayson works in a department store selling clothing. He makes a guaranteed salary
MrRissso [65]

Step-by-step explanation:

a) $350 per week

20% commission on sales

For $925 in sales, commission is

20/100 × 925 = $185

Total earning = $350 + $185 = $535

b) For $x in sales, commission is

20/100 × x = 1/5 × x = x/5 or 0.2x

Total earnings = $350 + $ x/5 or $350 + $0.2x

4 0
3 years ago
A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.
lana66690 [7]
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40 (at break even point)

2.05x^2 - 10x - 20 = 0

x =  [ - (-10) +/- sqrt(100 - 4*2.05*-20) / (2*2.05) 

x =  6.40, -1.52   Ignore the negative 

Answer is  6.40


3 0
3 years ago
The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviat
aleksley [76]

Answer:

4.5 hour and 2 hour

Step-by-step explanation:

Given: The mean number of hours per day spent watching television, according to a national survey, is 3.5 hours, with a standard deviation of two hours.

To Find: If each time was increased by one hour, what would be the new mean and standard deviation.

Solution:

let the total numbers entries of hours in survey be   =   \text{N}

each entry in survey be  =  \text{x}_{i}

mean of survey is     =     \mu  =3.5 \text{hours}

standard deviation is  =   \sigma = 2 \text{hours}

if each entry in survey is increased by one hour then,

each new entry in survey  is =  \text{x}_{i}+1

the new mean is\mu_{new}  = \frac{\text{sum of all hours}}{total number of entries}

                                                \frac{\text{x}_{1} +1+\text{x}_{2}+1 +....+\text{x}_{N}+1 }{N}

                                                \frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})+\text{N}\times1 }{N}

                                                \frac{(\text{x}_{1} +\text{x}_{2} +....+\text{x}_{N})}{N}+\frac{\text{N}\times1 }{N}

                                             \mu_{new} = \mu + 1=4.5 \text{hours}

now,

standard deviation is      \sigma_{new}= \sqrt{\sum_{1}^{N}\frac{(\text{x}_{inew}-\mu_{new})^{2}}{N}}

                                   \text{x}_{inew}= \text{x}_{i}+1

                                   \mu_{new}=\mu+1        

putting values,

                                                \sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}+1-\mu-1)^{2}}{N}}

                                                \sqrt{\sum_{1}^{N}\frac{(\text{x}_{i}-\mu)^{2}}{N}}= \sigma

                                 \sigma_{new}        =2

new mean and standard deviation are 4.5 and 2 \text{hours}

                                               

5 0
3 years ago
Pleaseeee help meeee
yan [13]
Don’t really know if you still need help
4 0
3 years ago
PLEASE HELP
loris [4]

Answer:

12 4 3232qwe

Step-by-step explanation:

6 0
3 years ago
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