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Zinaida [17]
3 years ago
10

11

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
3 0

Answer:

//

Step-by-step explanation:

Bill's answer is wrong because timesing 150 by 1.3 is increasing the number by 30%, not 3%

If he wanted to use this method, he would have ti times 150 by 1.03

Harman [31]3 years ago
3 0

Answer:

154.5

Step-by-step explanation:

Bill's method is wrong since 3% is equivalent to 0.03 or 3/100 and not 1.3 so this is where the mistake is. Moreover, Bill's method is not only wrong but also incomplete.

In order to increase 150 by 3% you will have to determine how much is 3% of 150 to have it increased by that specific amount.

<u>Calculations:</u>

150 x 0.03 = 4.5

Now that we know 4.5 is 3% of 150, we can add 4.5 to 150 to increase it by 3%.

150 + 4.5 = 154.5

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Helpppppp mathhh failing
LenKa [72]
Sin60 =b/10
<span>√3/2 = b/10
</span>b = <span>√3 / 2 (10)
</span>b = 5<span>√3
</span>
d^2  = 10^2 - (5√3)^2
d^2 = 100 - 75
d^2 = 25
d = 5

sin30 = b/a
1/2 = 5√3  / a

a = 5√3 (2)
a = 10√3

c^2 = (10√3)^2  -  (5√3)^2
c^2 = 300 - 75
c^2 = 225
c = 15

so
a =10√3,  b = 5√3, c = 15,d = 5
answer is
D. last choice

4 0
3 years ago
Eric bought a canoe for $333.75. The sales tax was 5.25%. What was his total cost?
Jobisdone [24]

Answer:

the answer is 397.32

Step-by-step explanation:

333.75 ÷ 5.25 = 397.32

8 0
2 years ago
The distance to the nearest exit door is less than 150 feet.
Alja [10]

Answer:

d<150

Step-by-step explanation:

6 0
3 years ago
DATA ANALYSIS AND STATISTICSProbabilities involving two rolls of a dieAn ordinary (falr) die is a cube with the numbers 1 throug
Zepler [3.9K]

Solution

The table below is the required sample space of the to fair die

From the above table

The sample space contain 36 outcomes

Event A: The sum is greater than 9

we will look at the table and count all the elements that are greater than 9

There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)

The probability for event A will be

\begin{gathered} p(A)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(A)=\frac{6}{36} \\ p(A)=\frac{1}{6} \end{gathered}

P(A) = 1/6

Event B: The sum is an even number.

We will look at the table and count the number of elements that are even

There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)

The probability for event B will be

\begin{gathered} p(B)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(B)=\frac{18}{36} \\ p(B)=\frac{1}{2} \end{gathered}

p(B) = 1/2

5 0
1 year ago
Anyone please help please
9966 [12]
I would say A,C,and D
6 0
3 years ago
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