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lions [1.4K]
3 years ago
14

How do i solve this?

Mathematics
1 answer:
pantera1 [17]3 years ago
8 0
The answer is x^2 - 4x +4. What I did was set it up as a ratio, FOILing out the two denominators on the left to get (x-5)?/(x^2 - 7x + 10) = (x+1)/1. Next I cross-multiplied to get (x-5)? = (x+1)(x^2 - 7x + 10). Next I FOILed out the right side to get (x-5)? = x^3 - 9x^2 + 24x - 20.  Now I have an equation just like 3x=9, for example, where I divide both sides by 3 to find x. Instead, since we have polynomials, we have to use long division. Divide the x^3 term by x-5 and you'll get it.
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Which two triangles are congruent ? Complete the congruence statement . Please don’t be wrong I’ll
lukranit [14]

Answer:

ΔHFG≅ΔSUT

Step-by-step explanation:

You just have to match up the sides and the angle.It's easier to color code them.

For example:

Segment SU would be congruent with HF. (both would be blue, just example color)

Angle U is congruent to angle F (red)

UT congruent to FG (green)

6 0
3 years ago
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mixas84 [53]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Please help please please
Marina CMI [18]

Answer:

C. y = 2x + 8

Step-by-step explanation:

✔️First, find the slope of the line that goes through points (-2, 4) and (6, 20):

Slope (m) = ∆y/∆x = (20 - 4) / (6 - (-2))

Slope (m) = 16/8

m = 2

✔️Find the y-intercept (b):

To do this, substitute (x, y) = (6, 20) and m = 2 into y = mx + b

Thus:

20 = 2(6) + b

20 = 12 + b

20 - 12 = b

8 = b

b = 8

✔️Write the equation by substituting m = 2 and b = 8 into y = mx + b

Thus:

y = 2x + 8

8 0
3 years ago
I dont get this problem
babymother [125]
The answer is 3

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