One way is to just expand it by using binomial theorem
or to use pascal's triangle
ok so
to find the nth term of a binomial, (a-b). where the binomial is to the r power you do
n-1=k
rCk times
![(a)^{r-k}(-b)^k](https://tex.z-dn.net/?f=%28a%29%5E%7Br-k%7D%28-b%29%5Ek)
and rCk=
![\frac{r!}{k!(r-k)!}](https://tex.z-dn.net/?f=%20%5Cfrac%7Br%21%7D%7Bk%21%28r-k%29%21%7D%20)
so
4th term
4-1=3
6 is exponent
6C3
![(3x)^{6-3}(-2y)^3](https://tex.z-dn.net/?f=%283x%29%5E%7B6-3%7D%28-2y%29%5E3)
=
![( \frac{6!}{3!(6-3)!} )((3x)^3(-8y^3)](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B6%21%7D%7B3%21%286-3%29%21%7D%20%29%28%283x%29%5E3%28-8y%5E3%29)
=
![( \frac{6*5*4}{1*2*3} )(27x^3)(-8y^3)](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B6%2A5%2A4%7D%7B1%2A2%2A3%7D%20%29%2827x%5E3%29%28-8y%5E3%29)
=
![(20)(27)(-8)(x^3)(y^3)=-4320x^3y^3](https://tex.z-dn.net/?f=%2820%29%2827%29%28-8%29%28x%5E3%29%28y%5E3%29%3D-4320x%5E3y%5E3)
the 4th term is
Answer:
Area of the sector = 29.48 square miles.
Step-by-step explanation:
Given:
Radius of a circle = 13 miles
Angle bounded by the arc = 20 deg
To find
Area of the sector bounded by 20 degrees.
Note: Area of a sector =
Plugging the values in the equation.
⇒ ![\frac{(\theta)}{360}\times \pi\times r^2](https://tex.z-dn.net/?f=%5Cfrac%7B%28%5Ctheta%29%7D%7B360%7D%5Ctimes%20%5Cpi%5Ctimes%20r%5E2)
⇒ ![(\frac{20}{360})\times 3.14\times 13^2](https://tex.z-dn.net/?f=%28%5Cfrac%7B20%7D%7B360%7D%29%5Ctimes%20%203.14%5Ctimes%2013%5E2)
⇒
square-miles
So the area of the sector bounded by 20 degree arc is 29.48 square miles.
The best thing to do is to rewrite the fractions as decimals
-2/3 is approx. equal to -0.6666667
So a little past half way (to the left) between -1 and 0
1 1/5 is 1.5 so that is right between 1 and 2
Hope this helps :)
Answer:
The answer is the third option from the top:
0, 0, 11, 15, 26, 32, 45, 46, 46, 46, 60, 71, 84, 88
3/4 = .75
4/7 = .57
the answer is : 3/4 > 4/7