The half-life of the given exponential function is of 346.57 years.
<h3>What is the half-life of an exponential function?</h3>
It is the value of t when A(t) = 0.5A(0).
In this problem, the equation is:
.
In which t is measured in years.
Hence the half-life is found as follows:
![0.5A(0) = A(0)e^{-0.002t}](https://tex.z-dn.net/?f=0.5A%280%29%20%3D%20A%280%29e%5E%7B-0.002t%7D)
![e^{-0.002t} = 0.5](https://tex.z-dn.net/?f=e%5E%7B-0.002t%7D%20%3D%200.5)
![\ln{e^{-0.002t}} = \ln{0.5}](https://tex.z-dn.net/?f=%5Cln%7Be%5E%7B-0.002t%7D%7D%20%3D%20%5Cln%7B0.5%7D)
![0.002t = -\ln{0.5}](https://tex.z-dn.net/?f=0.002t%20%3D%20-%5Cln%7B0.5%7D)
![t = -\frac{\ln{0.5}}{0.002}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7B%5Cln%7B0.5%7D%7D%7B0.002%7D)
t = 346.57 years.
More can be learned about exponential functions at brainly.com/question/25537936
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0.222 that goes on and on is 2/9
Answer:$207
Step-by-step explanation:
.55 times 300 is 165
.6 times 70 is 42
42 and 165 is 207
Mark me as brainliest if this helps!
C. â–łADE and â–łEBA
Let's look at the available options and see what will fit SAS.
A. â–łABX and â–łEDX
* It's true that the above 2 triangles are congruent. But let's see if we can somehow make SAS fit. We know that AB and DE are congruent, but demonstrating that either angles ABX and EDX being congruent, or angles BAX and DEX being congruent is rather difficult with the information given. So let's hold off on this option and see if something easier to demonstrate occurs later.
B. â–łACD and â–łADE
* These 2 triangles are not congruent, so let's not even bother.
C. â–łADE and â–łEBA
* These 2 triangles are congruent and we already know that AB and DE are congruent. Also AE is congruent to EA, so let's look at the angles between the 2 pairs of congruent sides which would be DEA and BAE. Those two angles are also congruent since we know that the triangle ACE is an Isosceles triangle since sides CA and CE are congruent. So for triangles â–łADE and â–łEBA, we have AE self congruent to AE, Angles DAE and BEA congruent to each other, and finally, sides AB and DE congruent to each other. And that's exactly what we need to claim that triangles ADE and EBA to be congruent via the SAS postulate.
Answer:
<em>-5/4</em>
Step-by-step explanation:
7(x + 4) + 1x - 9 * 2 = -8x + -10
Distribute 7 on left side. Multiply 9 * 2 on left side.
7x + 28 + 1x - 18 = -8x + -10
Combine like terms on left side.
8x + 10 = -8x + -10
Add 8x to both sides. Subtract 10 from both sides.
16x = -20
Divide both sides by 16.
x = -20/16
Reduce the fraction.
x = -5/4