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Marianna [84]
4 years ago
5

Fill in the blanks to complete the 4 part conclusion. There is suggestive, but inconclusive evidence the Velvetleaf seed beetle

is successful at weed control. The sample estimates the average percent of seeds to be infected by the beetle is 5.164, with a 95% confidence interval of 3.699 to 6.629 . We fail to reject the null hypothesis at a 0.05 significance level..
a) how suggestive or inconclusive
b) lower and upper bounds
c) reject or fail to reject

Mathematics
1 answer:
Anarel [89]4 years ago
3 0

Answer:

a) There is suggestive evidence the velvet leaf seed is successful at weed control.

b) Lower bound: 3.699 Upper bound: 6.629

c) Since the confidence interval contains the average percent of seeds to be infected by the beetle (5.164), so we fail to reject the null hypothesis at the specified level of significance.

Step-by-step explanation:

See attached picture.

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The diagonal of a rectangle is 25 in. The width is 15 in. What is the area of the triangle?
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First, find the length
L^2+W^2=D^2 )L for length, W for width, D for diagonal)
L^2=25^2-15^2=625-225=400
L=20
A=1/2 of L*W= (1/2)*20*15=150 square inches
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Blake thinks that the mass of a baby mouse will increase similar to what is shown on the graph below
Crank

Answer:

6 is the answer

Step-by-step explanation:

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Solve the inequality, if possible. If the inequality has no solution, write no solution. If the solutions are all real numbers,
Alina [70]
7 - 6b \leq 19 - 7 \\ \\ -6b \leq 12 \\ \\ b \geq  \frac{12}{-6} \\ \\ b \geq - \frac{12}{6} \\ \\ b  \geq  -2 \\ \\ Answer: b \geq -2
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4 years ago
Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i
bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1)  with respective to 'x'

\frac{dx}{dt} = 1+cost

differentiating equation (2)  with respective to 'y'

\frac{dy}{dt} = -sint

The length of curve is

\int\limits^\pi_\pi  {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt

\int\limits^\pi_\pi  \,   {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

\int\limits^\pi_\pi  \,   {\sqrt{(2+2cost } } \, dt

\sqrt{2} \int\limits^\pi_\pi  \,   {\sqrt{(1+1cost } } \, dt

again using formula, 1+cost = 2cos^2(t/2)

\sqrt{2} \int\limits^\pi _\pi  {\sqrt{2cos^2\frac{t}{2} } } \, dt

Taking common \sqrt{2} we get ,

\sqrt{2}\sqrt{2}  \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt

2(\int\limits^\pi _\pi  {cos\frac{t}{2} } \, dt

2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }

length of curve = 4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

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3 years ago
Can a "special point" of a graph be a relative minimum and a zero at the same time? explain
Grace [21]

Answer:

uh b is the answer

Step-by-step explanation:

8 0
3 years ago
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