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kirill115 [55]
3 years ago
13

A sample of gas has an initial volume of 3.00 L and an initial pressure of 2.14 atm. If the volume expands to 8.15 L, what is th

e final pressure?a. 0.855 atm b. 0.788 atm c. 3.49 atm d. 5.81 atm
Chemistry
1 answer:
Alla [95]3 years ago
6 0

Answer:

The final pressure is 0.788 atm (option b).

Explanation:

Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. That is: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases. This is expressed mathematically as the product of pressure times volume equal to a constant value:

P*V=k

Assuming a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1*V1=P2*V2

In this case:

  • P1= 2.14 atm
  • V1= 3 L
  • P2= ?
  • V2= 8.15 L

Replacing:

2.14 atm*3 L= P2* 8.15 L

Solving:

\frac{2.14 atm*3 L}{8.15 L} =P2

0.788 atm= P2

<u><em>The final pressure is 0.788 atm (option b).</em></u>

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