What is the ph category of each of the following i need help plz

Select the correct answer.

GREYUIT [131]

Answer:HNO3 + NaOH → H2O + NaNO3

Explanation:

8 0

3 years ago

A reaction has a rate constant of 1.15 x 10^−2 /s at 400K and 0.685 /s at 450K.

n200080 [17]

Answer:

a) the activation barrier = 122.3 kJ/mol

b) The rate constant at 425 K = 0.1001 /s

Explanation:

Step 1: Data given

Rate constant k1 = 1.15 * 10^−2 /s at 400K (= T1)

Rate constant k2 = 0.685 /s at 450K (=T2)

Step 2: Determine the activation barrier for the reaction.

To determine the activation energy we will use the two-point Arrhenius equation:

ln(k₂/k₁) = (Ea/R)((1/T1) - (1/T2))

⇒ with Ea = the activating energy

⇒ with R = the gas constant = 8.314 J/mol* K

⇒ with k1 = rate constant 1 = 1.15 *10^-2 /s

⇒ with T1 = Temperature 1 = 400 K

⇒ with k2 = rate constant 2 = 0.685/s

⇒ with T2 = temperature 2 = 450 K

= - (Ea/R)(T₁ - T₂)/T₁T₂

Ea = (R*ln (k2/k1)) / ((1/T1)- (1/T2))

Ea = (8.314* ln(0.685/0.0115)) / ((1/400) - (1/450))

Ea = 122327.6 = 122.3 kJ/mol

B) What is the value of the rate constant at 425 K

For rate constant at 425 K.

Substitute the value of activation energy as 122327.6 J/mol, initial temperature as 400 K, final temperature as 425 K, rate constant at 400 K

1/T1 - 1/ T3 = 1/400 - 1 /425 = 1.47*10^-4

⇒ with T1 = the initial temperature = 400 K

⇒ with k1 = the rate constant at 400 K = 1.15 * 10^-2 /s

⇒ with T3 = the nex temperature = 425 K

⇒ with k3 = the rate constant at 425 K

ln(k3/k1) = Ea/R * ((1/T1)- (1/ T3))

⇒ with k3 = the rate constant at 425 K

⇒ with T3 = 425 K

k3/k1 = e^(Ea/R * ((1/T1)- (1/ T3)))

k3 = k1* e^(Ea/R * ((1/T1)- (1/ T3)))

k3 = 0.0115 * e^(122327.6/8.314 * (1.4710^-4))

k3 = 0.0115* e^2.1643

k3 = 0.1001 /s

4 0

3 years ago

A material has an ASTM grain size number of 7. Determine the magnification, if the number of grains per square inch observed is:

Luden [163]

Answer:

A) M = 100X

B) M = 36X

C) M = 178.88X

Explanation:

Given data:

ASTM grain size number 7

a) total grain per inch^2 - 64 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have

$64 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 100 X

B) total grain per inch^2 = 500 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have $500 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 36 X

C) Total grain per inch^2 = 20 grain/inch^2

we know that number of grain per square inch is given as

$Nm = 2^{n-1} (\frac{100}{M})^2$

where M is magnification, n is grain size

therefore we have $20 = 2^{7-1}(\frac{100}{M})^2$

solving for M we get

M = 178.88 X

8 0

2 years ago

Why is the vapor pressure of a warm pale higher than the vapor pressure of a cold lake

levacccp [35]

The vapor pressure of a warm pale higher than the vapor pressure of a cold lake because Warm water evaporates more quickly.

Hence, Option B is correct answer.

<h3>What is Evaporation ? </h3>

The process in which a liquid or solid is converted into vapour is called Evaporation. When water gains the heat energy then it changes in to gas. When the temperature increases it speeds up the rate of evaporation.

The temperature of warm water increases, the kinetic energy of the warm water molecule also increases.

Thus from the above conclusion we can say that The vapour pressure of a warm lake is higher than the vapor pressure of a cold lake because Warm water evaporates more quickly.

Hence, Option B is correct answer.

Learn more about the Evaporation here: brainly.com/question/9339710

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete questions.

Question: Why is the vapor pressure of a warm lake higher than the vapor pressure of a cold lake?

A. Warm water has a greater heat of vaporization.

B. Warm water evaporates more quickly.

C. Cool water evaporates more quickly.

D. Cool water has a greater heat of vaporization.

3 0

1 year ago

How does the length of the day affect the seasonal temperature

astra-53 [7]

The longer the day, the solar radiation is absorbed and the higher the temperature is.

I hope you have a great rest of your day!

❤

6 0

3 years ago