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2 years ago

Which equation could be used to solve this problem?

Mathematics

1 answer:

vredina [299]2 years ago

6 0

The equation that represents how many items are on each list is option B) x + (x-9) = 33.

Step-by-step explanation:

There are two different lists of grocery.

The number of items in the 1st grocery list = x

The number of items in the 2nd grocery list differs by 9 from the number of items in the 1st grocery list.

Therefore, the number of items in the 2nd grocery list = (x-9)

The total number of items for both lists = 33.

The equation can be formed as :

number of items in the 1st list + number of items in the 2nd list = total number of items.

⇒ x + (x-9) = 33

The equation that represents how many items are on each list is x + (x-9) = 33.

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jeka57 [31]

Answer:

You can decide to reject the Null Hypothesis at p < 0.05.

Step-by-step explanation:

In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.

The categories of childhood trauma are:

Trauma and No trauma.

So, number of rows is, r = 2.

The categories of weight in adulthood are:

Low to normal, Overweight, and Obese

So, number of columns is, c = 3.

The distribution of the statistic $\chi^{2}$ is chi-square with (r - 1)(c - 1) degrees of freedom, where r represents the number of rows in the two-way table and c represents the number of columns.

Compute the degrees of freedom as follows:

$df = (r-1)(c-1)=(2-1) \times (3-1) = 2$

It is provided that the calculated value of Chi-square test statistic is 18.26.

Compute the p-value of the test as follows:

$p-value=P(\chi^{2}_{2}\geq 18.26)\\=0.000108\\\approx0.00011$

Decision rule:

The null hypothesis will be rejected if the p-value of the test is less than the significance level.

The significance level is, α = 0.05.

p-value = 0.00011 < α = 0.05.

The null hypothesis will be rejected at 5% level of significance.

Thus, the complete statement is:

"You can decide to reject the Null Hypothesis at p < 0.05."

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