Answer:
i beileve in this answer its a question of more than one salution, one salution and no solutions ................ so more than one salutions
Step-by-step explanation:
Answer:
R = 8,228,571.43 (Approx)
Step-by-step explanation:
Given:
R = x²/y
x = 4.8 x 10⁵
y = 2.8 x 10⁴
Find:
Value of R
Computation:
R = x²/y
R = (4.8 x 10⁵)²/ (2.8 x 10⁴)
R = 23.04 x 10¹⁰ / (2.8 x 10⁴)
R = 8.22857.. x 10⁶
R = 8,228,571.43 (Approx)
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
Answer:
There are 19 big marbles
Step-by-step explanation:
10a + 3b = 209
a = 3b
3b = 3b
10a + a = 209
11a = 209
a = 209/11
a = 19
Sixty eight and nine plus eleven equals 12