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morpeh [17]
3 years ago
6

Four friends share 3 fruits bars equally how much does each friend get

Mathematics
2 answers:
devlian [24]3 years ago
8 0
They each would get 3/4 
Cerrena [4.2K]3 years ago
3 0
3/4 = 0.75

each friend gets 0.75 of a bar
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Arrange the given numbers in descending order 4/5,0.09,4,9,2/4
egoroff_w [7]

Answer:

9,4,4/5,2/4,0.09

Step-by-step explanation:

Simple, countdown from 9.

5 0
3 years ago
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What is the solution to the system of linear equations?
Naya [18.7K]

Step-by-step explanation:

is connected to graph before u learn this u must know your graph

3 0
3 years ago
Lung cancer is the leading cause of cancer-related deaths in the United States. Researchers examined the idea of testing all Med
Sidana [21]

Answer:

a. P(C) = 0.03

   P(test+ | C) = 0.89

   P(test- | no C) = 0.93

b. Tree diagram is attached.

c. P(test+) = 0.0946

d. P(C | test+) = 0.2822  

Step-by-step explanation:

a. Let C denote Lung Cancer The probability that a heavy smoker will develop lung cancer is 3% i.e. 0.03.

If lung cancer is present, the CT scan result comes out to be positive 89% of the times while if lung cancer is not present, the results are negative 93% of the time. Let test+ denote that the test result is positive and test- denote that the test result is negative.

P(C) = 0.03

P(test+ | C) = 0.89

P(test- | no C) = 0.93

b. The first pair of branches represent whether the individual has cancer or not.

P(C) = 0.03

P(no C) = 1 - 0.03 = 0.97

The second pair of branches will represent if the test result came out positive or negative.

For patients with cancer, P(test+) = 0.89, P(test-) = 1 - 0.89 = 0.11

For patients with no cancer, P(test -) = 0.93, P(test+)= 1 - 0.93 = 0.07.

The tree diagram is attached as an image file.

c. P(test+) = P(C)*P(test+| C) + P(No C)*P(test+| No C)

                                = (0.03)(0.89) + (0.97)(0.07)

                                = 0.0267 + 0.0679

    P(test+) = 0.0946

d. P(C | test+) = P(C ∩ test+) / P(test+)

                       = P(C)*P(test+ | C) / P(test+)

                       = (0.03)*(0.89) / 0.0946

    P(C | test+) = 0.2822  

7 0
3 years ago
A family has 4 children: Ariel, Bob, Chris, and Diana. Assuming that all birth orders are equally likely.
sattari [20]

Answer:

A) 0.5

B) 0.375

C) 0.375

D) 0.167

Step-by-step explanation:

Let's call

a: Ariel

b: Bob

c: Chris

d: Diana

There are 4*3*2*1 = 24 total combinations to order the 4 children

A) Ariel is older than Diana in the following 12 cases:

a b c d

a b d c

a c b d

a c d b

a d b c

a d c b

b a c d

b a d c

b c a d

c a b d

c a d b

c b a d

Then, the probability is 12/24 = 0.5

B) The condition "Ariel is older than Diana, if it is given that Ariel is older than Bob" is satisfied in the six first cases and last three cases of before.

Then, the probability is 9/24 = 0.375

C) Ariel is older than Diana, if it is given that Chris is older than Diana, in the following cases:

a b c d

a c b d

a c d b

a d c b

b a c d

b c a d

c a b d

c a d b

c b a d

Then, the probability is 9/24 = 0.375

D) Ariel is older than Diana, if it is given that Diana is older than Bob, in the following cases:

a c d b

a d b c

a d c b

c a d b

Then, the probability is 4/24 = 0.167

7 0
3 years ago
Read 2 more answers
At a certain pizza parlor, % of the customers order a pizza containing onions, % of the customer's order a pizza containing saus
wel

Answer:

At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.

Step-by-step explanation:

Hello!

You have the following possible pizza orders:

Onion ⇒ P(on)= 0.36

Sausage ⇒ P(sa)= 0.35

Onions and Sausages ⇒ P(on∪sa)= 0.66

The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.

If two events are not mutually exclusive, you know that:

P(A∪B)= P(A)+P(B)-P(A∩B)

Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:

P(on∪sa)= P(on)+P(sa)-P(on∩sa)

P(on∪sa)+P(on∩sa)= P(on)+P(sa)

P(on∩sa)= P(on)+P(sa)-P(on∪sa)

P(on∩sa)= 0.36+0.35-0.66= 0.05

I hope it helps!

5 0
3 years ago
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