Answer:
Step-by-step explanation:
Height: h(t)= -0.2t^2+2t = 2t(-0.1t + 1)
-0.2t^2+2t is a quadratic expression with a = -0.2 and b = 2.
The ball reaches its max height at t = -b/(2a).
Here, t = -2 / (2·[-0.2] ), or t = 2/0.4 = 5 (sec)
The ball reaches its max height at at 5 sec.
The max ht. of the ball is h(5) = -0.2(5 sec)^2 + 2(5 sec) = (-5 + 10) sec, or 5 ft.
To determine after how many sec the ball reaches the ground, we set h(t) = 0 and solve for t:
h(t)= -0.2t^2+2t = 0 = 2t(-0.1t + 1). Thus, t = 0 sec or t = 10 sec
The ball reaches the ground again after 10 sec.
Answer:
Step-by-step explanation:
We are given the following in the question:
The relation between chirping of crickets and temperature is a linear function.
where and b are constants. T(N) is the the temperature in Fahrenheit and N is the number of chirps per minute.
"A cricket produces 113 chirps per minute at 73 degrees Fahrenheit"
"A cricket produces 172 chirps per minute at 87 degrees Fahrenheit"
Solving the two equations, we get,
Thus, the required linear function is:
it's going up and to the right (slope of 2/1 or up 2 right 1) through the point 0,-5 as you set x to 0 to get f(x)=2(0)-5 , f(x)=0-5, f(x)=-5. getting points 0,-5
I think so because I did this this year but I’m not sure
Answer:
It's parallel. Both have a slope of 3 and they have different y intercepts
Step-by-step explanation:
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