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polet [3.4K]
2 years ago
13

If A=−2x+8 and B=2x−4, find an expression that equals 2A+B in standard form.

Mathematics
1 answer:
kirza4 [7]2 years ago
5 0

Answer: -2x + 12

Step-by-step explanation:

2A + B = 2(-2x + 8) + (2x - 4) = -4x + 16 + 2x - 4 = -2x + 12

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3 years ago
Now simplify the y-terms to get the equation of the parabolic path. You do not need to expand the x-term. (2 points) Hint: Squar
aalyn [17]

The simplified equation of (x - 10)^2 + (y- 6)^2 = 4^2 is y = 6+  \sqrt{16 - (x - 10)^2}

<h3>How to determine the simplified equation?</h3>

The complete question is added as an attachment

The equation is given as

(x - 10)^2 + (y- 6)^2 = 4^2

Subtract (x - 10)^2 from both sides

(y- 6)^2 = 4^2 - (x - 10)^2

Evaluate 4^2

(y- 6)^2 =16 - (x - 10)^2

Take the square root of  both sides

y- 6= \sqrt{16 - (x - 10)^2}

Add 6 to both sides

y = 6+  \sqrt{16 - (x - 10)^2}

Hence, the simplified equation of (x - 10)^2 + (y- 6)^2 = 4^2 is y = 6+  \sqrt{16 - (x - 10)^2}

Read more about simplified equation at:

brainly.com/question/723406

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6 0
2 years ago
Which choice is equivalent to the quotient shown here when x &gt;= 0?
lisov135 [29]
√18x / √50

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C
4 0
4 years ago
Triangle JKL is transformed using the rule . Point K of the pre-image is at (4, 7). What are the coordinates of point K" on the
Zanzabum

Answer:

Option C.

Step-by-step explanation:

Consider the complete question is "Triangle JKL is transformed using the rule R(O,90^\circ)\circ r_{y=-x}(x,y). Point K of the pre-image is at (4, 7). What are the coordinates of point K'' on the final image?".

According to r_{y=-x}(x,y), we get

(x,y)\rightarrow (-y,-x)

According to R(O,90^\circ), we get

(x,y)\rightarrow (-y,x)

The rule R(O,90^\circ)\circ r_{y=-x}(x,y) means first reflection and then rotation.

We need to find the image of K(4,7).

After reflection, we get

K(4,7)\rightarrow K'(-7,-4)

After rotation, we get

K'(-7,-4)\rightarrow K''(4,-7)

Therefore, the correct option is C.

8 0
3 years ago
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L = 10.5 + 2.75

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