I think
Step-by-step explanation:
12.5 since it decreases 10% and the old bag had 14 cups and 10% is 1.4
The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0
t 1 = - 0.05
t 2 = 3.8
Answer:
C ) 3.80 s
9514 1404 393
Answer:
1.63 cm (across the centerline from release)
Step-by-step explanation:
If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...
h(t) = -7cos(2πt/4)
h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm
That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.
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If it is released from <em>above</em> the resting position, it will be 1.63 cm <em>below</em> the resting position at t=1.15 seconds.
X = 2/3 makes the equation true.
Answer: x = 2/3
Answer:
The higher number would be the one that more people are getting
Step-by-step explanation: