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3 years ago

Answer the last one please answer fast

Mathematics

1 answer:

Oduvanchick [21]3 years ago

4 0

Answer:

Step-by-step explanation:

Put the equation in the form ax+by+c=0:

$y\sqrt{3} =8x+\sqrt{3} \\=>8x-\sqrt{3} y+\sqrt{3} =0$

Check the solutions:

$(0,-1)$ :

$8(0)-\sqrt{3} (-1)+\sqrt{3} =2\sqrt{3}$

So this is not a solution.

( $(\sqrt{3} ,9)$ :

$8\sqrt{3} -9\sqrt{3} +\sqrt{3} =0$

So this is a solution

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Sector problem please help

hammer [34]

Answer:

The answer is (π/4)*r

Step-by-step explanation:

Formula length of arc when the angle given is in radian as the case given

s = r*θ

s = arc length (in radians)

r = radius

θ = central angle in radians

But when the angle given is in degrees the length is expressed as

s= 2πr*(θ/360)

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4 years ago

Find the equation of the axis of symmetry for the parabola y = x2 + 2x − 9

Artemon [7]

Answer:

the answer is x=-1

Step-by-step explanation:

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3 years ago

Read 2 more answers

The two figures shown are congruent. which statement is true?

Masteriza [31]

Answer:

1st Option

Step-by-step explanation:

Hope it helps

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3 years ago

Read 2 more answers

Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r

NeTakaya

$\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}$

<h2>Explanation:</h2>

In this exercise, we have the following functions:

$r(x)=2x-1 \\ \\ s(x)=5x$

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

$(r-s)(x)$

That is, we subtract s(x) from r(x):

$(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}$

Second expression:

$(r\cdot s)(x)$

That is, we get the product of s(x) and r(x):

$(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}$

Third expression:

Here we need to evaluate:

$(r+s)(-2)$

First of all, we find the sum of functions r(x) and s(x):

$(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1$

Finally, substituting x = -2:

$(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}$

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0

3 years ago

Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first three terms is 26.

Serga [27]

Answer:

<h3>The nth term Tn = -8(-1/4)^(n-1) or Tn = 6(1/3)^(n-1) can be used to find all geometric sequences</h3>

Step-by-step explanation:

Let the first three terms be a/r, a, ar... where a is the first term and r is the common ratio of the geometric sequence.

If the sum of the first two term is 24, then a/r + a = 24...(1)

and the sum of the first three terms is 26.. then a/r+a+ar = 26...(2)

Substtituting equation 1 into 2 we have;

24+ar = 26

ar = 2

a = 2/r ...(3)

Substituting a = 2/r into equation 1 will give;

(2/r))/r+2/r = 24

2/r²+2/r = 24

(2+2r)/r² = 24

2+2r = 24r²

1+r = 12r²

12r²-r-1 = 0

12r²-4r+3r -1 = 0

4r(3r-1)+1(3r-1) = 0

(4r+1)(3r-1) = 0

r = -1/4 0r 1/3

Since a= 2/r then a = 2/(-1/4)or a = 2/(1/3)

a = -8 or 6

All the geometric sequence can be found by simply knowing the formula for heir nth term. nth term of a geometric sequence is expressed as

if r = -1/4 and a = -8

Tn = -8(-1/4)^(n-1)

if r = 1/3 and a = 6

Tn = 6(1/3)^(n-1)

The nth term of the sequence above can be used to find all the geometric sequence where n is the number of terms

6 0

3 years ago