Question

Answer the last one please answer fast

Answer 1

Answer:

Step-by-step explanation:

Put the equation in the form ax+by+c=0:

$y\sqrt{3} =8x+\sqrt{3} \\=>8x-\sqrt{3} y+\sqrt{3} =0$

Check the solutions:

$(0,-1)$:

$8(0)-\sqrt{3} (-1)+\sqrt{3} =2\sqrt{3}$

So this is not a solution.

($(\sqrt{3} ,9)$:

$8\sqrt{3} -9\sqrt{3} +\sqrt{3} =0$

So this is a solution