The table shows how the compound interest on an investment of $6,000 with an interest rate of 3 34%, compounded annually, grows
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Answer:
The amount of phosphorus-32 left after 100.1 days is <u>9.3 g</u>.
Step-by-step explanation:
Given:
Initial amount of Phosphorus-32 is,
Time period of decay is,
Half life of the block is,
Now, final amount left is,
We know that, the decay equation for a radioactive material is given as:
The value of the decay constant is given as:
Now, plug in all the given values and calculate 'N'. This gives,
Therefore, the amount of phosphorus-32 left after 100.1 days is 9.3 g