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taurus [48]
3 years ago
10

1) In the year 2010, Shaniya invested $1 in the stock market. In the year 2022, her $1 was worth $2. In the year 2034, it was wo

rth $4. In the year 2046, it was worth $8. How much will Shaniya's investment be worth in the year 2370?
(Due tomorrow at 1)
Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

$1,073,741,824

Step-by-step explanation:

Every 12 years, the price increases by double. So, first we would need to find the difference of years between 2370 and 2046.

2370-2046=324

Divide this number by 12 to see how many times the number is doubled.

324/12=27

Continue this pattern of "every 12 years, the price increases by 2x" 27 times.

Ex: 2058-->$16

Ex: 2070-->$32

Ex: 2082-->$64

etc....

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2 1/8 x+ 3/4 x+ 1/6 − 7/12 x+5 2/3
AleksAgata [21]

Answer:

x = (-28)/11

Step-by-step explanation:

Solve for x:

(55 x)/24 + 35/6 = 0

Put each term in (55 x)/24 + 35/6 over the common denominator 24: (55 x)/24 + 35/6 = (55 x)/24 + 140/24:

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(55 x)/24 + 140/24 = (55 x + 140)/24:

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Multiply both sides of (55 x + 140)/24 = 0 by 24:

(24 (55 x + 140))/24 = 24×0

(24 (55 x + 140))/24 = 24/24×(55 x + 140) = 55 x + 140:

55 x + 140 = 24×0

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55 x + 140 = 0

Subtract 140 from both sides:

55 x + (140 - 140) = -140

140 - 140 = 0:

55 x = -140

Divide both sides of 55 x = -140 by 55:

(55 x)/55 = (-140)/55

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The gcd of 140 and 55 is 5, so (-140)/55 = (-(5×28))/(5×11) = 5/5×(-28)/11 = (-28)/11:

Answer: x = (-28)/11

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3 years ago
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Step-by-step explanation:

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165*100 = 16.5 
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