Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
Rewrite 7/8 as a decimal by dividing 7 by 8:
7/8 = 0.875
Now to find how much further she has to run subtract where is now from the total distance:
0.875 - 0.3 = 0.575
She needs to run 0.575 miles more
