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2 years ago

7

Please help due soon

1 answer:

Alik [6]2 years ago

8 0

Answer:

5z^2-8z+3

-5×-3=15

-5+-3=-8

so...

5z^2-5z-3z+3

5z(z-1)-3(z-1)

therefore the answer is...

(5z-3) (z-1)

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The points A(0, 0), B(0, 4a - 5) and C(2a + 1, 2a + 6) form a triangle. If angle ABC = 90, what is the area of triangle ABC?(A)

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Answer:

A:102

Step-by-step explanation:

We are given that the points A(0,0),B(0,4a-5) and C(2a-+1,2a+6) form a triangle.

If angle ABC= $90^{\circ}$

We have to find the area of triangle ABC

If angle ABC= 90 degree

From given below figure

$4a-5=2a+6$

$4a-2a=6+5$

$2a=11$

$a=\frac{11}{2}=5.5$

Substitute the values then we get

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Distance formula

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

AB= $\sqrt{(0-0)^2+(17-0)^2}=17 units$

BC= $\sqrt{(12-0)^2+(17-17)^2}$

BC= $\sqrt{144+0}=\sqrt{144}=12$ units

Area of triangle = $\frac{1}{2}\times b\times h$

Substitute the values

Then we get

Area of triangle ABC= $\frac{1}{2}\times 17\times 12$

Area of triangle ABC=102 square units

Answer: A: 102

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