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3 years ago

Can someone please tell me how to add an attachment/picture so I can for my next/actual question

Mathematics

2 answers:

Viktor [21]3 years ago

6 0

Answer:

Go to the paperclip emblem and add the attached image!

tresset_1 [31]3 years ago

4 0

When you ask a question, above the subject and points, there is a little paper clip where you can add pictures. Hope this helped!

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Simplify the expression -4x2(3x − 7).

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-12x^3 + 28x^2

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4 years ago

Based on the figure below, the ratio of x/y is equivalent to which trigonometric function?

Ede4ka [16]

Answer: OPTION D.

Step-by-step explanation:

For this exercise it is important to remember the following Trigonometric Functions:

$sin\alpha =\frac{opposite}{hypotenuse}\\\\cos\alpha =\frac{adjacent}{hypotenuse}\\\\tan\alpha =\frac{opposite}{adjacent}\\\\sec\alpha =\frac{hypotenuse}{adjacent}\\\\csc\alpha =\frac{hypotenuse}{opposite}\\\\cot\alpha =\frac{adjacent}{opposite}$

Knowing this, we can identify that:

$cosA=\frac{AC}{AB}=\frac{x}{AB}\\\\sinB=\frac{AC}{AB}=\frac{x}{AB}\\\\secA=\frac{AB}{AC}=\frac{AB}{x}\\\\tanB=\frac{AC}{BC}=\frac{x}{y}$

Therefore, the ratio $\frac{x}{y}$ is equivalent to this Trignometric function:

$tanB=\frac{x}{y}$

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4 years ago

Factorise 3x^3 - 12xy^2

igomit [66]

Answer:

we can conclude that:

$3x^3\:-\:12xy^2=3x\left(x+2y\right)\left(x-2y\right)$

Step-by-step explanation:

Given the expression

$3x^3-12xy^2$

Let us factorize the expression

$3x^3-12xy^2$

Apply the exponent rule: $a^{b+c}=a^ba^c$

$3x^3\:-\:12xy^2=3xx^2-12xy^2$

Rewrite 12 as 4 · 3

$=3xx^2-4\cdot \:3xy^2$

Factor out the common term 3x

$=3x\left(x^2-4y^2\right)$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$=3x\left(x+2y\right)\left(x-2y\right)$

Therefore, we can conclude that:

$3x^3\:-\:12xy^2=3x\left(x+2y\right)\left(x-2y\right)$

8 0

3 years ago