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GalinKa [24]
3 years ago
7

Factorise 3x^3 - 12xy^2​

Mathematics
1 answer:
igomit [66]3 years ago
8 0

Answer:

we can conclude that:

3x^3\:-\:12xy^2=3x\left(x+2y\right)\left(x-2y\right)

Step-by-step explanation:

Given the expression

3x^3-12xy^2

Let us factorize the expression

3x^3-12xy^2

Apply the exponent rule: a^{b+c}=a^ba^c

3x^3\:-\:12xy^2=3xx^2-12xy^2

Rewrite 12 as 4 · 3

                     =3xx^2-4\cdot \:3xy^2

Factor out the common term 3x

                     =3x\left(x^2-4y^2\right)

\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)

                      =3x\left(x+2y\right)\left(x-2y\right)

Therefore, we can conclude that:

3x^3\:-\:12xy^2=3x\left(x+2y\right)\left(x-2y\right)

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