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Anuta_ua [19.1K]
3 years ago
12

Brainly solve 100 points

Mathematics
2 answers:
telo118 [61]3 years ago
7 0

Answer:

1.9059 x 10 -12

Step-by-step explanation:

almond37 [142]3 years ago
4 0
Answer: it’s f- by the millisecond
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find the x- and y-intercept of the line. 5x – 4y = 40 a. x-intercept is –4; y-intercept is 5. b. x-intercept is –10; y-intercept
pashok25 [27]
5x - 4y = 40

x intercept is when y = 0

5x - 4*0 = 40

5x = 40

x = 40/5

x = 8             x intercept = 8

y intercept is when x = 0

5*0  - 4y = 40

-4y = 40

y = 40/-4

y = -10

y intercept = -10


x intercept = 8, <span>y intercept = -10</span>
4 0
3 years ago
Jonah and Graham are working together. Jonah claims that (x+y)^2 = x^2+y^2. Graham is sure Jonah is wrong, but he cannot figure
brilliants [131]

Answer:

Here is what I got hope it helps!!!!!!!

Step-by-step explanation:

5 0
3 years ago
Find the equation in slope intercept form the describes a line with slope -2 and y intercept 4<br>​
levacccp [35]

Step-by-step explanation:

The equation is y = 4 - 2x.

7 0
3 years ago
Read 2 more answers
GIVING OUT BRAINLIEST TO WHOEVER GETS ALL OF THEM RIGHT
Thepotemich [5.8K]

Answer:

4) \frac{x}{7\cdot x +x^{2}} is equivalent to \frac{1}{7+x} for all x \ne -7. (Answer: A)

5) \frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}} is equivalent to -\frac{14}{1-5\cdot x} for all x \ne \frac{1}{5}. (Answer: B)

6) \frac{x+7}{x^{2}+4\cdot x - 21} is equivalent to \frac{1}{x-3} for all x \ne 3. (Answer: None)

7) \frac{x^{2}+3\cdot x -4}{x+4} is equivalent to x - 1. (Answer: None)

8)  \frac{2}{3\cdot a}\cdot \frac{2}{a^{2}} is equivalent to \frac{4}{3\cdot a^{3}} for all a\ne 0. (Answer: A)

Step-by-step explanation:

We proceed to simplify each expression below:

4) \frac{x}{7\cdot x +x^{2}}

(i) \frac{x}{7\cdot x +x^{2}} Given

(ii) \frac{x}{x\cdot (7+x)} Distributive property

(iii) \frac{1}{7+x} \cdot \frac{x}{x} Distributive property

(iv) \frac{1}{7+x} Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

7+x = 0

x = -7

Hence, we conclude that \frac{x}{7\cdot x +x^{2}} is equivalent to \frac{1}{7+x} for all x \ne -7. (Answer: A)

5) \frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}}

(i) \frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}} Given

(ii) \frac{x^{3}\cdot (-14)}{x^{3}\cdot (1-5\cdot x)} Distributive property

(iii) \frac{x^{3}}{x^{3}} \cdot \left(-\frac{14}{1-5\cdot x} \right) Distributive property

(iv) -\frac{14}{1-5\cdot x} Commutative property/Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

1-5\cdot x = 0

5\cdot x = 1

x = \frac{1}{5}

Hence, we conclude that \frac{-14\cdot x^{3}}{x^{3}-5\cdot x^{4}} is equivalent to -\frac{14}{1-5\cdot x} for all x \ne \frac{1}{5}. (Answer: B)

6) \frac{x+7}{x^{2}+4\cdot x - 21}

(i) \frac{x+7}{x^{2}+4\cdot x - 21} Given

(ii) \frac{x+7}{(x+7)\cdot (x-3)} x^{2} -(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})

(iii) \frac{1}{x-3}\cdot \frac{x+7}{x+7} Commutative and distributive properties.

(iv) \frac{1}{x-3} Existence of multiplicative inverse/Modulative property/Result

Rational functions are undefined when denominator equals 0. That is:

x-3 = 0

x = 3

Hence, we conclude that \frac{x+7}{x^{2}+4\cdot x - 21} is equivalent to \frac{1}{x-3} for all x \ne 3. (Answer: None)

7) \frac{x^{2}+3\cdot x -4}{x+4}

(i) \frac{x^{2}+3\cdot x -4}{x+4} Given

(ii) \frac{(x+4)\cdot (x-1)}{x+4}  x^{2} -(r_{1}+r_{2})\cdot x +r_{1}\cdot r_{2} = (x-r_{1})\cdot (x-r_{2})

(iii) (x-1)\cdot \left(\frac{x+4}{x+4} \right) Commutative and distributive properties.

(iv) x - 1 Existence of additive inverse/Modulative property/Result

Polynomic function are defined for all value of x.

\frac{x^{2}+3\cdot x -4}{x+4} is equivalent to x - 1. (Answer: None)

8) \frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}

(i) \frac{2}{3\cdot a}\cdot \frac{2}{a^{2}}

(ii) \frac{4}{3\cdot a^{3}} \frac{a}{b}\cdot \frac{c}{d} = \frac{a\cdot b}{c\cdot d}/Result

Rational functions are undefined when denominator equals 0. That is:

3\cdot a^{3} = 0

a = 0

Hence, \frac{2}{3\cdot a}\cdot \frac{2}{a^{2}} is equivalent to \frac{4}{3\cdot a^{3}} for all a\ne 0. (Answer: A)

6 0
3 years ago
If spot eats 156 pounds of food each year and he eats the same amount each month, how much does he eat in 1 month?
nekit [7.7K]

One year is 12 months and you want to know how much Spot eats in one month. So your going to divide 156 by 12 to get the amount of food eaten in one month.

156/12= 13 pounds

7 0
3 years ago
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