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Scilla [17]
3 years ago
7

Whats the best answer for this equation: 4(b - 4) ; b = 5

SAT
1 answer:
icang [17]3 years ago
8 0
The answer to this is 4
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Which of the following is ordered from greatest to least?
Alex777 [14]

Answer: 3rd option: 0.23, 0.2, -0.35, -0.56

Explanation: 0.23 is 0.03 greater than 0.2 so 0.23 is first, 0.2 is 0.85 greater than -0.35, so it is the second number, and finally -0.35 is 0.21 greater than -0.56 which makes -0.35 the third number and -0.56 the last number.

Hope this helps! :)

5 0
3 years ago
Which table of values was used to create the scatterplot below?.
d1i1m1o1n [39]

Answer:

Its C

Explanation:

1 200

2 300

3 200

4 400

5 300

8 0
3 years ago
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Shalnov [3]

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3 years ago
What is the volume of this right prism? 96 in³ 60 in³ 48 in³ 44 in³
boyakko [2]

Option C) 48in³ is the correct answer.

Hence, the volume of the right triangular prism is 48in³.

This question is incomplete, the missing diagram is uploaded along this answer.

Given the data in the question;

  • Side length a; a = 4in
  • Side length b; b = 5in
  • Side length c; c = 3in
  • Height; h = 8in

Volume; V = \ ?

<h3>Volume of right triangular Prism</h3>

Volume is simply the space created when a surface is enclosed , it is the space that a quantity material that can be held.

The volume of a right triangular prism can be expressed as;

V = \frac{1}{4}h\sqrt{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}

To determine the volume of the right triangular prism, we substitute our given values into the expression above.

V = \frac{1}{4}h\sqrt{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}\\\\V = \frac{1}{4}*8in*\sqrt{(4in+5in+3in)(5in+3in-4in)(3in+4in-5in)(4in+5in-3in)}\\\\V = \frac{1}{4}*8in*\sqrt{(12in)(4in)(2in)(6in)}\\\\V = \frac{1}{4}*8in*\sqrt{576in^4}\\\\V = \frac{1}{4}*8in*24in^2\\\\V = \frac{1}{4} * 192in^3\\\\V = 48in^3

Option C) 48in³ is the correct answer.

Hence, the volume of the right triangular prism is 48in³.

Learn more about volume of right triangular prism : brainly.com/question/17208216

4 0
3 years ago
Compare and contrast the normal distribution with the standard normal distribution. Here are a few things to keep in mind as you
igomit [66]

Answer:

Both are normal distributions but standard normal distribution is a particular case of Normal distribution when the mean is 0 and standard deviation or variance is 1. This makes Y a “Standard” distribution. So basically X is Normally distributed and Y is “Standard” normally distributed.

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3 years ago
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