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TEA [102]
2 years ago
12

Which ones are rational and which are irrational?

Mathematics
1 answer:
In-s [12.5K]2 years ago
3 0

Answer:

irrational, irrational, irrational, rational, rational

Step-by-step explanation:

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What are the solutions to the equation <br><img src="https://tex.z-dn.net/?f=2%20%7Cx%20-%202%7C%20%20-%208%20%3D%2020" id="TexF
leva [86]

The solutions of the equation are -12 and 16

Step-by-step explanation:

Absolute value describes the distance of a number on the number line from 0 without considering which direction from zero the number lies. The absolute value of a number is never negative, if IxI = a, where a > 0, then

  • x = a
  • x = -a

∵ 2Ix - 2I - 8 = 20

- At first add 8 to both sides

∴ 2Ix - 2I = 28

- Then divide both sides by 2

∴ Ix - 2I = 14

Now By using the notes above equate x - 2 by 14 and -14

∵ x - 2 = 14

- Add 2 to both sides

∴ x = 16

∵ x - 2 = -14

- Add 2 to both sides

∴ x = -12

The solutions of the equation are -12 and 16

Learn more:

You can learn more about solving equations in brainly.com/question/2386054

#LearnwithBrainly

4 0
3 years ago
11. What is the reciprocal of 6/5?<br> OA. 12/20<br> OB.11/5<br> OC.1<br> OD.576
Elanso [62]

Answer: The answer is D, 5/6.

Step-by-step explanation: The reciprocal of a fraction is that fraction but the numerator and denominater swapped places.

3 0
3 years ago
Read 2 more answers
Simplify 2(a+5)−3(5a−4)
Nutka1998 [239]

Answer:

-13a+22

Step-by-step explanation:

we have

2(a+5)-3(5a-4)

step 1

Apply the distributive property  both terms

2a+2(5)-3(5a)+3(4)

2a+10-15a+12

step 2

Combine like terms

(2a-15a)+(10+12)

(-13a)+(22)

-13a+22

4 0
2 years ago
Solve for x and y:<br> 3/x -1/y =13/10<br> 1/x + 2/y =9/10
harkovskaia [24]

Answer:

  (x, y) = (2, 5)

Step-by-step explanation:

I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...

  3x' -y' = 13/10

  x' +2y' = 9/10

Adding twice the first equation to the second, we get ...

  2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)

  7x' = 35/10 . . . . . . simplify

  x' = 5/10 = 1/2 . . . . divide by 7

Using the first equation to find y', we have ...

  y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5

So, the solution is ...

  x = 1/x' = 1/(1/2) = 2

  y = 1/y' = 1/(1/5) = 5

  (x, y) = (2, 5)

_____

The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.

3 0
3 years ago
Any equation can be written in function notation<br> O True<br> False
Fynjy0 [20]

Answer: True

Step-by-step explanation:

7 0
2 years ago
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