Answer:
0.6708 or 67.08%
Step-by-step explanation:
Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:

There is a 0.6708 probability that Helen makes both free throws.
 
        
             
        
        
        
The width would be 236 and the lengths would be 118
Use the equations 2L+W=472 and W*L=MAX
Change the first equation to W=472-2L and plug this into the other equation
(472-2L)(L)=MAX
472L-2L^2=M (take derivative)
472-4L=0 (set to 0 to find the max value)
4L=472 
L=118 
Plug into original to get W=236
Hope this helps!
        
             
        
        
        
Step-by-step explanation:
options are wrong 
this is wrong options 
tge answer is underoot 200