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Y_Kistochka [10]
3 years ago
9

(easy math question please help) find the value of x question #4 again

Mathematics
1 answer:
olganol [36]3 years ago
8 0

Answer:

x = -26.67 (this is rounded the real answer is 26.6666...)

Step-by-step explanation:

180 - (46 + 36) = 82 (the measure of the last angle)

82 = (2 - 3x)

(subtract two from both sides)

80 = (-3x)

(divide both sides by -3)

-26.67=x

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Which ordered pair is a solution to the system of equations?<br> (2x - y=-2<br> (5x – 2y = 7
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What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²
AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

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A = (-1,0)

B = (5,-3)

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To Find:

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Solution:

We know that Area of Rhombus is given as

\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}

Where ,

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We have,

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Using Distance Formula we get

l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting coordinates A and C we get

l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit

Similarly for BD we have,

l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit

Now Substituting AC and BD in Formula we get

\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD

\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}

Therefore the Area of Rhombus ABCD is 36 unit².

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3 years ago
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Step-by-step explanation:

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ivanzaharov [21]

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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