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ad-work [718]
4 years ago
9

Television sizes are described by the length of their diagonal measure. What would be the listed size of the TV shown? (to the n

earest whole inch)
A) 31 inches
B) 32 inches
C) 36 inches
D) 42 inches

Mathematics
2 answers:
Lisa [10]4 years ago
7 0
The answer is, B

hope this is correct 


Flauer [41]4 years ago
6 0

Here the television is of the shape of a rectangle.

If we draw a diagonal then it will divide the rectangle into two right angled triangles.

So we have to find length of hypotenuse in this case that will be diagonal itself.

The measure of two legs are ,

28 in. and 15.7 in.

Now in a right angled triangle pythagoras theorem is applied as :

a^{2}+b^{2}=c^{2}

where a and b are legs of the triangle and c is hypotenuse.

So plugging values of a and b,

(28)^{2}+(15.7)^{2}=c^{2}

784+246.49=c^{2}

1030.49=c^{2}

c=32.101

So diagonal is 32.101 inches.

Rounding off it equals 32 inches.

Answer: The size of television is 32 inches. option B.

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