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3 years ago

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The top of a ladder rests at a height of 15 feet against the side of a house. If the base of the ladder is 6 feet from the house

, what is the length of the ladder? Round to the nearest foot.
Please help

2 answers:

Ksju [112]3 years ago

6 0

90
15 x 6 = 90
You need to multiply

cupoosta [38]3 years ago

4 0

Well I would use that and put in a equation

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Oksi-84 [34.3K]

the answer is D :) i hope you have a good day

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Please solve the equation _4(4n+2)=4

MrRissso [65]

16n+8=4
16n=4-8
16n=-4
n=-4/16
n=-1/4.

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2 years ago

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Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3

AlexFokin [52]

The ODE is separable, i.e. you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx$

Integrating both sides gives the general solution.

$\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx$
$y=-\ln|\cos x|+C$

Given that $y\left(\dfrac\pi4\right)=3$ , we have

$3=-\ln\left|\cos\dfrac\pi4\right|+C$
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3 years ago

Ali simplifies the expression 9y+y to 9y2. Use the drop-down menus to complete the statements below to explain why Ali's solutio

maxonik [38]

Ali's solution is incorrect.

Ali had to add both the terms and should get 10y answer, and not multiply both terms and get answer 9y^2 which is wrong.

Step-by-step explanation:

Ali simplifies the expression 9y+y to 9y2. We need to identify if Ali's solution is correct or incorrect.

Ali's solution is incorrect.

Reason:

We are given the expression: 9y+y

When we add two like terms ( terms having the same variable and exponent), we add the coefficients of both like terms.

In our case 9y+y = 10y

Whereas Ali has done multiplication of both terms and not addition.

In multiplication we add the exponents of the same variables i.e 9y+y = 9y^2

So, Ali had to add both the terms and should get 10y answer, and not multiply both terms and get answer 9y^2 which is wrong.

Keywords: Solving expressions

Learn more about Solving expressions at:

#learnwithBrainly

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3 years ago

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Nadya [2.5K]

To solve this we are going to use the exponential function: $f(t)=a(1(+/-)b)^t$
where
$f(t)$ is the final amount after $t$ years
$a$ is the initial amount
$b$ is the decay or grow rate rate in decimal form
$t$ is the time in years

Expression A
$f(t)=624(0.95)^{4t}$
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate $b$ , we are going to use the formula: $b=|1-base|$ *100%
$b=|1-0.95|$ *100%
$b=0.05$ *100%
$b=$ 5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at $t=0$
$f(t)=624(0.95)^{4t}$
$f(0)=624(0.95)^{0t}$
$f(0)=624(0.95)^{0}$
$f(0)=624(1)$
$f(0)=624$
We can conclude that the initial value of expression A is 624.

Expression B
$f(t)=725(1.12)^{3t}$
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
$b=|1-base|$ *100%
$b=|1-1.12|$ *100
$b=|-0.12|$ *100%
$b=0.12$ *100%
$b=$ 12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at $t=0$
$f(t)=725(1.12)^{3t}$
$f(0)=725(1.12)^{0t}$
$f(0)=725(1.12)^{0}$
$f(0)=725(1)$
$f(0)=725$
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.

- Expression A has an initial value of 624, while expression B has an initial value of 725.

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2 years ago