<span>A) Joey used 10 congruent triangles to create a regular decagon.
What kind of triangles is he using?
He is using isosceles triangles. because the two sides (of each triangle) whose vertix is at the center of the decagon are congruent, while the third side, is different.
b)Joey used 10 congruent triangles to create a regular decagon.
Find the three angle measures of one of the triangles. Explain how you know.
The angle between the two congruent sides is equal to 360° divided by the number of triangles.
360° / 10 = 36.
The other two angles are congruent and must obey the rule of 180°.
2x + 36 = 180 => 2x = 180 - 36 = 144
x = 144 / 2 = 72°
Then two angles are 72° and the other is 36°.
c)Joey used 10 congruent triangles to create a regular decagon.
If the area of each triangle is 14.5 square inches, then what is the area of the regular decagon? Show all work.
The area of the decagon is ten times the area of a triangle.
Area of the decagon = 10 * 14.5 in^2 = 145 in^2.
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Answer:
The distance is 5 square root of 5, or if it asks in decimal form it would be 11.180.
Step-by-step explanation:
To find the distance between any points, you must use the distance formula. When you plug in the points given, you end up with 11.180. I hope this helps!
Answer:
? = 14
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp /adj
tan ? = 8/33
Taking the inverse tan of each side
tan ^-1 ( tan ?) = tan ^-1 ( 8/33)
? =13.62699
To the nearest degree
? = 14
Distance traveled = 360 meter
Time taken = 8:04 - 8:01 = 3 min= 180 s
Velocity = 360/180 = 2 m/s
Hope this helps!
<span><span><span>82</span>=64</span><span><span>82</span>=64</span></span>choices for that.
Now, for the second one, we can't be in the row or column of that first one, so leaving us with <span><span><span>72</span>=49</span><span><span>72</span>=49</span></span> choices.
Then so on, we have <span><span><span>62</span>=36</span><span><span>62</span>=36</span></span> for the third one, <span>2525</span> for the fourth one, and so on <span>……</span>
But, however, we have to remember the rooks are not labeled, thus it doesn't matter specifically about a specific rook's position.
Thus, we have a total of <span><span><span><span>(8!<span>)2</span></span><span>8!</span></span>=40320</span><span><span><span>(8!<span>)2</span></span><span>8!</span></span>=40320</span></span> ways.