Complete the square to rewrite y = x^2 – 6x + 2 in vertex form. Then state whether the vertex is a maximum or a minimum and give
1 answer:
In order to complete the square, the leading coefficient has to be a positive 1, which it is. Now we will set the polynomial equal to 0 and move the 2 over by subtraction to isolate the x terms. 
. The rule now is to take half the linear term, square it, and then add it in to both sides. Our linear term is 6. Half of 6 is 3, and 3 squared is 9, so we add 9 to both sides. 
. Simplifying we have 
. During this process, and the reason for it, was to create a perfect square binomial on the left which will give us the x coordinate (or the h) for our vertex. That perfect square binomial is 
. Now we will move the 7 over by subtraction and set the polynomial back equal to y to get 
. Our vertex, then, is (3, -7) and this is a min value since our parabola is positive and opens up like a cup that has a bottom instead of mountain that has a top. And there you go! Your answer is C
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Answer:
a. There is evidence that the population mean is above $300.
b. There is no evidence that the population mean is above $300.
c. There is no evidence that the population mean is above $300.
d. The director could ask for cheaper similar books.
Step-by-step explanation:
Let X be the random variable that represents the cost of textbooks. We have observed n = 25 values, = 315.4 and s = 43.20. We suppose that X is normally distributed.
We have the following null and alternative hypothesis
vs
(upper-tail alternative)
We will use the test statistic
and the observed value is
.
If is true, then T has a t distribution with n-1 = 24 degrees of freedom.
a. The rejection region is given by RR = {t | t > } where
is the 90th quantile of the t distribution with 24 df, so, RR = {t | t > 1.3178}. Because the observed value satisty 1.7824 > 1.3178, there is evidence that the population mean is above $300.
b. If s = 75, then the observed value is . The rejection region for a 0.05 level of significance is RR = {t | t >
} where
is the 95th quantile of the t distribution with 24 df, so, RR = {t | t > 1.7108}. Because the observed value does not fall inside the rejection region, there is no evidence that the population mean is above $300.
c. If and s = 43.20, the observed value is
. For RR = {t | t > 1.3178} we have that the observed value does not fall inside RR, therefore, there is no evidence that the population mean is above $300.
d. Because the director of admissions is concerned about the high cost of textbooks, and there is evidence that the population mean of costs is above $300, the director could ask for cheaper similar books.