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3 years ago

Determine the equation of the graph.

Mathematics

1 answer:

ruslelena [56]3 years ago

6 0

Answer: C

y=-5cos(x) is the graphed equation. Cos(x) starts at (0,0) and one period is 2pi or 6.28 and by cos(x) multiplied by -5 starts the cosine wave at (0,-5) and thus corresponds to the graphed equation shown.

Any questions please feel free to ask. Thanks

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Which translation maps the vertex of the graph of the function f(x) = x2 onto the vertex of the function g(x) = x2 – 10x +2? rig

patriot [66]

Hey there! :)

Answer:

Right 5, down 23

Step-by-step explanation:

Beginning with the parent function f(x) = x²:

Find the translations of the graph g(x) by completing the square to rewrite the equation in vertex form:

g(x) = x² - 10x + 2

-2 = x² - 10x

-2 + 25 = (x² - 10x + 25)

23 = (x - 5)²

Rewrite:

g(x) = (x - 5)² - 23

The translations that we can see from this equation in vertex form are a horizontal translation of 5 units right and 23 units down. Therefore:

Right 5, down 23 is the correct choice.

6 0

4 years ago

In the above triangle, if x = , y = 1, and z = 2, then which of the following is equal to tan(60°)?

vesna_86 [32]

Answer: Option A

$tan(60\°) = \sqrt{3}$

Step-by-step explanation:

We know the sides and z. So since it is a straight triangle we use the Pythagorean theorem to pull the length of the x side.

$z ^ 2 = x ^ 2 + y ^ 2\\\\x^2 = z^2 - y^2\\\\x=\sqrt{z^2 - y^2}\\\\x=\sqrt{2^2 - 1^2}\\\\x=\sqrt{4 - 1}\\\\x=\sqrt{3}$

By definition, the tangent of an angle is:

$tan(\theta) = \frac{opposite}{adjacent}$

In this case:

$adjacent = y=1\\\\opposite=x =\sqrt{3}\\\\\theta=60\°$

Then:

$tan(60\°) = \frac{\sqrt{3}}{1}$

$tan(60\°) = \sqrt{3}$

8 0

4 years ago

Read 2 more answers

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ArbitrLikvidat [17]

Answer:

I think ur answer would be

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