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2 years ago

The equation x2 – 1x – 90 = 0 has solutions {a, b}. What is a + b

2 answers:

8 0

X^2 - x - 90 =0
This equation is in standard form ax^2+ bx + c
The sum of the solutions is -b/a (a and b are the coefficients from the equation above, not the solutions to the equation)
The answer is 1/1 = 1

REY [17]2 years ago

3 0

Answer:

Step-by-step explanation:

Alright, let get started.

The given equation is : $x^2-1x-90=0$

This is a quadratic equation.

The standard form of a quadratic equation is : $AX^2+BX+C=0$

Comparing the given equation with standard one, the values of A ,B and C are :

A is 1

B is -1

C is -90

Since a and b are the roots of the equation, so the formula for sum of roots a+b will be = $\frac{-B}{A}$

a+b= $-\frac{-1}{1} =1$

hence a+b will be 1 : Answer

Hope it will help :)

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2 years ago

Keith has $500 in a savings account at the beginning of the summer. He withdraws $25 each week for food, clothes, and movie tick

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You can put this solution on YOUR website!

the inequality is 500 - 25x >= 200

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simplify to get 300 >= 25x

divide both sides of that equation by 25 to get 300 / 25 >= x

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when x is smaller than or equal to 12, he will be guaranteed to have at least 200 in the account at the end of the summer.

when x = 12, what is left in the account is 500 - 25 * 12 = 200.

when x = 11, what is left in the account is 500 - 25 * 11 = 225.

when x = 13, what is left in the account is 500 - 25 * 13 = 175.

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Step-by-step explanation:

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2 years ago

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2 years ago

If g(x)=4x-6 then g^-1(x)=? (1) -4x+6 (2)-1/4x+1/6 (3)1/4x+3/2 (4)1/4x+6

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Given:

$g(x)=4x-6$

To find:

The function $g^{-1}(x)$ .

Solution:

we have,

$g(x)=4x-6$

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Interchange x and y.

$x=4y-6$

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$x+6=4y$

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Substitute $y=g^{-1}(x)$ .

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