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liubo4ka [24]
3 years ago
13

What is the slope of a line that goes through (0,0) amd (5,-1)

Mathematics
2 answers:
iren2701 [21]3 years ago
6 0
(0, 0) and (5, -1)

Slope equation : m = (y₂-y₁) / (x₂-x₁)

Plug everything in :)

m = (-1 - 0) / (5 - 0)

Simplify.

m = -1/5

So, the slope is -1/5

~Hope I helped!~


statuscvo [17]3 years ago
3 0
Slope of line is -1/5 !!!!!!!!!!!
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Helium is pumped into a spherical balloon at a rate of 3 cubic feet per second. How fast is the radius increasing after 2 minute
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Answer:

The rate of change of radius is 0.0530 ft/sec.

Step-by-step explanation:

Given : Helium is pumped into a spherical balloon at a rate of 3 cubic feet per second.

To find : How fast is the radius increasing after 2 minutes?

Solution :

The volume of the sphere is V=\frac{4}{3}\pi r^3

Differentiating w.r.t. r,

\frac{dV}{dr}=4\pi r^2

We have given, Helium is pumped into a spherical balloon at a rate of 3 cubic feet per second.

i.e. \frac{dV}{dt}=3

Integrate w.r.t. t,

V=3t+C

Assuming V=0 when  t=0 then C=0

So, \frac{4}{3}\pi r^3=3t

r^3=\frac{t}{4\pi}

r=\sqrt[3]{\frac{t}{4\pi}}

Now, we apply chain rule

i.e.  \frac{dV}{dt}=\frac{dV}{dr}\cdot \frac{dr}{dt}

3=4\pi(\frac{t}{4\pi})^{\frac{2}{3}}\cdot \frac{dr}{dt}

The radius increasing after 2 minutes i.e. at t=2\times 60=120

3=4\pi(\frac{120}{4\pi})^{\frac{2}{3}})\cdot \frac{dr}{dt}

3=56.56\cdot \frac{dr}{dt}

\frac{dr}{dt}=\frac{3}{56.56}

\frac{dr}{dt}=0.0530

Therefore, the rate of change of radius is 0.0530 ft/sec.

8 0
3 years ago
True or false? ( help me please and thank you)
Dmitriy789 [7]

Answer:

False

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Just follow these steps!

Non-zero digits are always significant.

Any zeros between two significant digits are significant.

A final zero or trailing zeros in the decimal portion ONLY are significant.

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Answer:

it is 55%

Step-by-step explanation:

I think it is 55 %

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LenaWriter [7]

Answer:

Meter

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