<em>BD</em> = 56
Step-by-step explanation:
Step 1: In rectangle, the diagonals are congruent and bisect each other.
So, <em>AC</em> = <em>BD</em>
⇒<em>AG</em> + <em>GC</em> = <em>BG</em> + <em>GD</em>
⇒<em>AG</em> + <em>AG</em> = <em>GD</em> + <em>GD</em>
⇒ 2<em>AG</em> = 2<em>GD</em>
⇒<em>AG</em> = <em>GD</em>
⇒ –7<em>j </em>+ 7 = 5<em>j</em> + 43
⇒–7<em>j</em> – 5<em>j</em> = 43 – 7
⇒–12<em>j</em> = 36
⇒<em>j</em> = –3
Step 2: <em>BD</em> = 2<em>DG</em>
<em>BD</em> = 2(5<em>j</em> + 43)
= 2(5 (–3) + 43)
= 2(–15 + 43)
= 2 × 28
= 56
Hence, <em>BD</em> = 56.
They are all the same amount of blocks.
The percentage of the offspring that will have atatched earlobes as the dominant trait, is: 50%.
What is a Dominant Trait?
A dominant trait surpresses a recessive trait, and expresses itself. The allele of a dominant trait is usally denoted using capital letters.
Given the following traits:
A - attached earlobes (dominant allele)
a - unattached earlobes (recessive allele)
A cross between Aa and aa is shown in the image attached below.
The offspring having attached earlobes = 2 Aa = 50%.
50% of the osspring will have attached earlobes.
Learn more about dominant trait on:
brainly.com/question/16616523