The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k? A) j = 6 and k = –10 B) j = 8 and k =
10 C) j = 4 and k = 25 D) j = 4 and k = 10
2 answers:
Answer:
j = 4 and k = 10
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
8x³ - 125 is a difference of cubes and factors in general as
a³ - b³ = (a - b)(a² + ab + b²)
here 8x³ = (2x)³ ⇒ a = 2x and 125 = 5³ ⇒ b = 5
8x³ - 125 = (2x - 5)((2x)² + (2x × 5) + 5²) = (2x - 5)(4x² + 10x + 25 )
compare the coefficients of like terms with jx² + kx + 25
jx² = 4x² ⇒ j = 4 and kx = 10x ⇒ k = 10 → D
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