The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k? A) j = 6 and k = –10 B) j = 8 and k =
10 C) j = 4 and k = 25 D) j = 4 and k = 10
2 answers:
Answer:
j = 4 and k = 10
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
8x³ - 125 is a difference of cubes and factors in general as
a³ - b³ = (a - b)(a² + ab + b²)
here 8x³ = (2x)³ ⇒ a = 2x and 125 = 5³ ⇒ b = 5
8x³ - 125 = (2x - 5)((2x)² + (2x × 5) + 5²) = (2x - 5)(4x² + 10x + 25 )
compare the coefficients of like terms with jx² + kx + 25
jx² = 4x² ⇒ j = 4 and kx = 10x ⇒ k = 10 → D
You might be interested in
Answer:
Yes i do the answer is C
Step-by-step explanation:
Have a good day:))))
-4/2=-2
(-2)^2=4
the blank is +4
x^2-4x+4
factored
(x-2)^2
Answer:
x= 4
2x-1=9
simplify 9-1 to 8
Divide both sides by 2
x=8/2
Simplify 8/2 to 4
x=4
Answer:
b
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
xy=k
Value of k ; when ; x = - 3 and y = - 2
Put x = - 3 and y = - 2 into the equation :
(-3)(-2) = k
-3 * - 2 = k
6 = k
The constant of variation k = 6
