The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k? A) j = 6 and k = –10 B) j = 8 and k =

Question

3 years ago

14

10 C) j = 4 and k = 25 D) j = 4 and k = 10

2 answers:

Radda [10] · Answer 1 · 2022-03-25T18:03:05+03:00

Radda [10]3 years ago

7 0

Answer:

j = 4 and k = 10

Step-by-step explanation:

Zinaida [17] · Answer 2 · 2022-03-25T16:59:42+03:00

Answer:

D

Step-by-step explanation:

8x³ - 125 is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²)

here 8x³ = (2x)³ ⇒ a = 2x and 125 = 5³ ⇒ b = 5

8x³ - 125 = (2x - 5)((2x)² + (2x × 5) + 5²) = (2x - 5)(4x² + 10x + 25 )

compare the coefficients of like terms with jx² + kx + 25

jx² = 4x² ⇒ j = 4 and kx = 10x ⇒ k = 10 → D