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frosja888 [35]
3 years ago
14

I need help ive completely forgot about like terms over the years

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
Like terms are terms that have something in common like an exponent or variable 

8. 3a & 16a
9. 5x^3 &7x^3
10. 6b^2 & b^2
11. 12t^2 & 4t^2 &2t^2

Try 12 & 13 on your own to see if you get the hang of it - if you want me to check it ; put your answer in the comment section of my answer :))) I believe in you .
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These four numbers are plotted on a number line: -2/3 5/8 -3/5 -1/2 Which is the correct ordering on the number line, from left
Yuki888 [10]

Answer:

-2/3 -3/5 -1/2 3/8

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3 0
2 years ago
Yx*2; use x=7,And y=2
Mars2501 [29]

Answer:

14*2

Step-by-step explanation:

x=7 and Y=2

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What is the name of the period that has the digits 751 in the number 751,486
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I hope this helps
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3 years ago
Give the trigonometric ratio as a fraction:<br> Tan Z<br> X<br> 24<br> 26<br> Y<br> 10<br> z
yulyashka [42]

Answer:

your answer is B

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A communications company offers a variety of calling card options. Card A has a 30¢ connection fee and then costs 2¢ per minute.
arlik [135]

Answer:

The length of the call that would cost the same with both cards is 5 minutes.

Step-by-step explanation:

Hi there!

The cost with card A can be expressed as follows:

cost A = 30 + 2 · m

Where "m" is the length of the call in minutes.

In the same way, the cost of card B will be:

cost B = 10 + 6 · m

Where "m" is the length of the call in minutes.

We have to find the value of "m" for which the call would cost the same with both cards.

Then:

cost A = cost B

30 + 2 · m = 10 + 6 · m

Subtract 10 and 2 · m to both sides of the equation:

30 - 10 =  6 · m - 2 · m

20 = 4 · m

Divide by 4 both sides of the equation:

20/4 = m

5 = m

The length of the call that would cost the same with both cards is 5 minutes.

Have a nice day!

3 0
3 years ago
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