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frosja888 [35]
3 years ago
14

I need help ive completely forgot about like terms over the years

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
Like terms are terms that have something in common like an exponent or variable 

8. 3a & 16a
9. 5x^3 &7x^3
10. 6b^2 & b^2
11. 12t^2 & 4t^2 &2t^2

Try 12 & 13 on your own to see if you get the hang of it - if you want me to check it ; put your answer in the comment section of my answer :))) I believe in you .
You might be interested in
A student solved for the radius of a circle with a circumference of 12π
padilas [110]

Answer:

Step 4 is incorrect  he did not divide correctly from step3 to step 4

Step-by-step explanation:

The circumference of a circle is

C = 2 * pi *r

We know the circumference is 12 pi

12pi = 2 pi *r

Divide each side by 2 pi

12 pi/2pi = 2pi r/ 2pi

6 = r

From step 3 The student did not cancel the pi in the top and the bottom on the right hand side to isolate r

In step 4 he got 6 =pi r  instead of pi

3 0
3 years ago
Solve the following by elimination method <br> 11x+15y+23=0 and 7x-2y-20=0
mr Goodwill [35]
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)

Multiply equation (1) by 2:
22x + 30y + 46 = 0

Multiply equation (2) by 15:
105x - 30y - 300 = 0

Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]

Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3

Therefore, x = 2 and y = -3.
7 0
3 years ago
Find the tangent line equation of the curve at the given point. Y=arcsin(7x) at the point where x=sqrt2/14
Mumz [18]

Answer:

Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})

Step-by-step explanation:

The equation of the curve is

Y = sin^{-1}(7x)

To find the equation of tangent we need to differentiate this equation w.r.t x

So, differentiating we get

Y'=\frac{7}{\sqrt{1-49x^2} }

This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is  x = \sqrt{\frac{1}{7} }

Then slope would accordingly be

Y'=\frac{7}{\sqrt{1-49/49} }

= ∞

For, x = \sqrt{\frac{1}{7} }, Y = sin^{-1}(7/7)= \pi/2

Equation of tangent line, in the point slope form, would be Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})

4 0
3 years ago
How to write y-1=-x-6 In slope intercept form
DiKsa [7]

y=-x-5. you just need to add 1 to another side to get rid of 1 from the left side

4 0
3 years ago
Read 2 more answers
WILL MARK BRAINLYEST
Nadusha1986 [10]

Answer:

17576

Step-by-step explanation:

As L can be anything from A to Z , there are 26 combinations for that and as repetition is allowed, for second and third letters, we again have 26 combinations available and thus 26×26×26=17576 combinations for letters.

5 0
3 years ago
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