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miss Akunina [59]
3 years ago
9

A circle has a diameter of 26 units. What is the area of the circle to the nearest hundredth of a square unit? Use 3.14 for pi.

*
Mathematics
1 answer:
Sholpan [36]3 years ago
5 0
A=pi(r)^2

We have the diameter. To get the radius divide it by 2.

The radius now is equal = 13.
Pi=3.14

Distribute it to the equation... A=3.14(13)^2

The area is equal = 530.66
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Área 9 perímetro 20 what is the leigh and width
bixtya [17]

Answer:

4.5 x 2

Step-by-step explanation:

4.5 x 2 = 9

Hope it helps

5 0
3 years ago
Willis tower in Chicago is 1450 feet tall. The John Hancock Center in Chicago is 1127 feet tall. Suppose you are asked to build
gayaneshka [121]

Answer:

Small Scale replica of John Hancock tower is approximately 2.33 m.

Step-by-step explanation:

Given:

Height of Willis tower = 1450 ft

Height of John Hancock Center = 1127 ft

Small Scale replica of Willis tower = 3 m

We need to find Small Scale replica of John Hancock tower.

First we will find the per meter scale of Willis tower and then using the same we will use to find the Small Scale replica height of John Hancock tower.

For 3 meter scaling = 1450 ft

So for 1 meter scaling = Number of foots in 1 meter Scaling

By Using Unitary method we get;

Number of foots in 1 meter Scaling = \frac{1450}{3} = 483.333 \ ft

Now we had 1 meter scaling as 483.333 ft and we need to find meter scaling for 1127.

So again Using Unitary method we get;

Small Scale replica of John Hancock = \frac{1127}{483.333} = 2.331 \ m

Rounding to nearest hundred we get;

Small Scale replica of John Hancock tower is approximately 2.33 m.

8 0
3 years ago
If z=15, what would the expression z2 – 2z + 15 be equal to?
svet-max [94.6K]

Answer:

15

Step-by-step explanation:

z2 - 2z + 15

(15)2 - 2(15) + 15

30 - 30 + 15

0 + 15

15

5 0
3 years ago
Read 2 more answers
HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER
NeTakaya

Step-by-step explanation:

x=90°

SUM OF ALL ANGLES OF PENTAGON =540

90+2(180-Y)+105+113=540

90+360-2Y+105+113=540

488-2Y=540

7 0
3 years ago
Read 2 more answers
From our lesson, what is your difficulty in dealing with exponential expressions?
aleksandrvk [35]

Answer:

From the said lesson, the difficulty that I have been trough in dealing over the exponential expressions is the confusion that frequently occurs across my system whenever there's a thing that I haven't fully understand. It's not that I did not actually understand what the topic was, but it is just somewhat confusing and such. Also, upon working with exponential expressions — indeed, I have to remember the rules that pertain to dealing with exponents and frequently, I will just found myself unconsciously forgetting what those rule were — rules which is a big deal or a big thing in the said lesson because it is obviously necessary/needed over that matter. Surely, it is also a big help for me to deal with exponential expressions since it's so much necessary — it's so much necessary but I keep fogetting it.. hence, that's why I call it a difficulty. That's what my difficulty. And in order to overcome that difficulty, I will do my best to remember and understand well the said rules as soon as possible.

3 0
2 years ago
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