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melamori03 [73]

3 years ago

8

What are the steps to solving the area of this compound shape?

1 answer:

Ymorist [56]3 years ago

4 0

Step-by-step explanation:

2Li+2H2O—>2LiOH+H2

Calculate the mass of reacted lithium when H2 is 6.02 * 10 ^ 23 molecules.

I really need the answer with all the calculation please.

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How many hundred thousands equal 80,000 tens

kumpel [21]

The answer is 8 hoped that help always fell free to comment me if you have any more questions and always good luck

3 0

3 years ago

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Please help with this question!!

xxMikexx [17]

$\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2\\\\l\perp k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\\text{We have the points J(-24, -4) and K(-4, 6)}.\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{substitute:}\\\\m_1=\dfrac{6-(-4)}{-4-(-24)}=\dfrac{10}{20}=\dfrac{1}{2}\\\\\text{therefore}\ m_2=-\dfrac{1}{\frac{1}{2}}=-2\\\\\text{The formula of a midpoint:}\\\\\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)\\\\\text{substitute the coordinates of the points J and K:}$

$x=\dfrac{-24+(-4)}{2}=\dfrac{-28}{2}=-14\\\\y=\dfrac{-4+6}{2}=\dfrac{2}{2}=1\\\\\text{midpoint}\ (-14,\ 1)\\\\\text{The point-slope form:}\\\\y-y_1=m(x-x_1)\\\\\text{substitute}\ m=-2,\ x_1=-14\ \text{and}\ y_1=1:\\\\y-1=-2(x-(-14))\\\\\boxed{y-1=-2(x+14)}$

8 0

3 years ago

What is 5/8ths of 48 , I need help I really don't get it

Bess [88]

$\frac58\ \cdot\ 48=\\=\frac58\ \cdot\ \frac{48}{1}=\\=\frac51\ \cdot\ \frac61=\\=5\ \cdot\ 6=\\=30$

6 0

4 years ago

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There are 48 people who have signed up to attend the midnight barbecue at the Rainbow Canyon Recreation Center. The chef wants t

BARSIC [14]

A) 264 11/2 *48
B) 66 pounds of beef needed .25*264
C) 66 pounds

6 0

3 years ago

if a quadratic equation with real coefficients has a discriminant of -36 then what type of roots does it have

Aleks04 [339]

Step-by-step explanation:

We have,

If a quadratic equation with real coefficients has a discriminant of -36.

The general form of quadratic equation is :

$ax^2+bx+c=0$

The discriminant of this equation is : $D=b^2-4ac$

If D=0, it will have 1 real roots

If D>0, it will have 2 real roots

If D<0, it will have no real roots

We have,

D = -36 < 0, so, the quadratic equation will have no real roots.

5 0

3 years ago